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js构建二叉树进行数值数组的去重与优化详解

前言

本文主要介绍了关于js构建二叉树进行数值数组的去重与优化的相关内容分享出来供大家参考学习,下面话不多说了,来一起看看详细的介绍吧。

常见两层循环实现数组去重

rush:js;"> let arr = [11,12,13,9,8,7,1,2,5,11,6,4,2] let newArr = [] for (let i = 0; i < arr.length; i++) { let unique = true for (let j = 0; j < newArr.length; j++) { if (newArr[j] === arr[i]) { unique = false break } } if (unique) { newArr.push(arr[i]) } } console.log(newArr)

构建二叉树实现去重(仅适用于数值类型的数组)

将先前遍历过的元素,构建成二叉树,树中每个结点都满足:左子结点的值 < 当前结点的值 < 右子结点的值

这样优化了判断元素是否之前出现过的过程

若元素比当前结点大,只需要判断元素是否在结点的右子树中出现过即可

若元素比当前结点小,只需要判断元素是否在结点的左子树中出现过即可

insert(value) {
let node = new Node(value)
if (!this.root) {
this.root = node
this.arr.push(value)
return this.arr
}
let current = this.root
while (true) {
if (value > current.value) {
if (current.right) {
current = current.right
} else {
current.right = node
this.arr.push(value)
break
}
}
if (value < current.value) {
if (current.left) {
current = current.left
} else {
current.left = node
this.arr.push(value)
break
}
}
if (value === current.value) {
break
}
}
return this.arr
}
}

let binaryTree = new BinaryTree()
for (let i = 0; i < arr.length; i++) {
binaryTree.insert(arr[i])
}
console.log(binaryTree.arr)

优化思路一,记录最大最小值

记录已经插入元素的最大最小值,若比最大元素大,或最小元素小,则直接插入

insert(value) {
let node = new Node(value)
if (!this.root) {
this.root = node
this.arr.push(value)
this.max = value
this.min = value
return this.arr
}
if (value > this.max) {
this.arr.push(value)
this.max = value
this.findMax().right = node
return this.arr
}
if (value < this.min) {
this.arr.push(value)
this.min = value
this.findMin().left = node
return this.arr
}
let current = this.root
while (true) {
if (value > current.value) {
if (current.right) {
current = current.right
} else {
current.right = node
this.arr.push(value)
break
}
}
if (value < current.value) {
if (current.left) {
current = current.left
} else {
current.left = node
this.arr.push(value)
break
}
}
if (value === current.value) {
break
}
}
return this.arr
}

findMax() {
let current = this.root
while (current.right) {
current = current.right
}
return current
}

findMin() {
let current = this.root
while (current.left) {
current = current.left
}
return current
}
}

let binaryTree = new BinaryTree()
for (let i = 0; i < arr.length; i++) {
binaryTree.insert(arr[i])
}
console.log(binaryTree.arr)

优化思路二,构建红黑树

构建红黑树,平衡树的高度

有关红黑树的部分,请见

class Node {
constructor(value) {
this.value = value
this.left = null
this.right = null
this.parent = null
this.color = 'red'
}
}

class RedBlackTree {
constructor() {
this.root = null
this.arr = []
}

insert(value) {
let node = new Node(value)
if (!this.root) {
node.color = 'black'
this.root = node
this.arr.push(value)
return this
}
let cur = this.root
let inserted = false
while (true) {
if (value > cur.value) {
if (cur.right) {
cur = cur.right
} else {
cur.right = node
this.arr.push(value)
node.parent = cur
inserted = true
break
}
}

if (value < cur.value) {
if (cur.left) {
cur = cur.left
} else {
cur.left = node
this.arr.push(value)
node.parent = cur
inserted = true
break
}
}

if (value === cur.value) {
break
}
}
// 调整树的结构
if(inserted){
this.fixTree(node)
}
return this
}

fixTree(node) {
if (!node.parent) {
node.color = 'black'
this.root = node
return
}
if (node.parent.color === 'black') {
return
}
let son = node
let father = node.parent
let grandFather = father.parent
let directionFtoG = father === grandFather.left ? 'left' : 'right'
let uncle = grandFather[directionFtoG === 'left' ? 'right' : 'left']
let directionStoF = son === father.left ? 'left' : 'right'
if (!uncle || uncle.color === 'black') {
if (directionFtoG === directionStoF) {
if (grandFather.parent) {
grandFather.parent[grandFather.parent.left === grandFather ? 'left' : 'right'] = father
father.parent = grandFather.parent
} else {
this.root = father
father.parent = null
}
father.color = 'black'
grandFather.color = 'red'

father[father.left === son ? 'right' : 'left'] && (father[father.left === son ? 'right' : 'left'].parent = grandFather)
grandFather[grandFather.left === father ? 'left' : 'right'] = father[father.left === son ? 'right' : 'left']

father[father.left === son ? 'right' : 'left'] = grandFather
grandFather.parent = father
return

} else {
grandFather[directionFtoG] = son
son.parent = grandFather

son[directionFtoG] && (son[directionFtoG].parent = father)
father[directionStoF] = son[directionFtoG]

father.parent = son
son[directionFtoG] = father
this.fixTree(father)

}
} else {
father.color = 'black'
uncle.color = 'black'
grandFather.color = 'red'
this.fixTree(grandFather)
}
}
}

let redBlackTree = new RedBlackTree()
for (let i = 0; i < arr.length; i++) {
redBlackTree.insert(arr[i])
}
console.log(redBlackTree.arr)

其他去重方法

通过 Set 对象去重

rush:js;"> [...new Set(arr)]

通过 sort() + reduce() 方法去重

排序后比较相邻元素是否相同,若不同则添加至返回的数组中

值得注意的是,排序的时候,compare(2,'2') 返回 0;而 reduce() 时,进行全等比较

{ let res = a - b if (res !== 0) { return res } else { if (a === b) { return 0 } else { if (typeof a === 'number') { return -1 } else { return 1 } } } }).reduce((pre,cur) => { if (pre !== cur) { newArr.push(cur) return cur } return pre },null)

通过 includes() + map() 方法去重

!newArr.includes(a) && newArr.push(a))

通过 includes() + reduce() 方法去重

{ !pre.includes(cur) && pre.push(cur) return pre },[])

通过对象的键值对 + JSON 对象方法去重

{ if(!obj[JSON.stringify(a)]){ obj[JSON.stringify(a)] = 1 } }) console.log(Object.keys(obj).map(a => JSON.parse(a)))

总结

以上就是这篇文章的全部内容了,希望本文的内容对大家的学习或者工作具有一定的参考学习价值,如果有疑问大家可以留言交流,谢谢大家对编程之家的支持

原文地址:https://www.jb51.cc/js/33013.html

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