SQLServer 2008查找所有行的总和以及行的组件总和

/ *我在sqlServer 2008中查询时遇到问题,要查找所有行的总和和行的各部分的总和.我使用了ROW_NUMBER(),outer_apply,但我无法解决问题.我在你的网站stack_overflow上搜索了几天,但我找不到类似的东西.
现在我甚至不知道怎么做.
谁能帮我？？？

输入数据：段号,初始节点,最终节点,区域,段是两个节点之间的距离.每个节点属于一个特定区域. * /

A       B       C      D        
--------------------------------
Section Initial Final  Area     
Number  Node    Node                  
================================
1       0       1      0    
2       1       2      5    
3       2       3      3.1  
4       3       4      3.7  
5       4       5      2.7  
6       5       6      0    
7       6       7      4.1  
8       7       8      0    
9       8       9      2.8  
10      9       10     4.6  
11      10      11     3.2
12      11      12     3    
13      12      13     5    
14      13      14     3.5  
15      1       15     3    
16      15      16     5.6  
17      16      17     4.7  
18      17      18     2.8   
19      6       19     0    
20      19      20     3.8  
21      20      21     5    
22      19      22     2.9  
23      8       23     4.4

/ *需要计算属于网络中每个节点的累积区域(Area Cum).
结果应该是* /

A       B       C     D        E        F
-----------------------------------------------------
Section Initial Final  Area     Area     Description
Number  Node    Node            Cum               
=====================================================
1       0       1       0       72.9    =SUM(D1:D23)
2       1       2       5       56.8    =SUM(D2:D14)+SUM(D19:D23)
3       2       3       3.1     51.8    =SUM(D3:D14)+SUM(D19:D23)
4       3       4       3.7     48.7    =SUM(D4:D14)+SUM(D19:D23)
5       4       5       2.7     45      =SUM(D5:D14)+SUM(D19:D23)
6       5       6       0       42.3    =SUM(D6:D14)+SUM(D19:D23)
7       6       7       4.1     30.6    =SUM(D7:D14)+D23
8       7       8       0       26.5    =SUM(D8:D14)+D23
9       8       9       2.8     22.1    =SUM(D9:D14)
10      9       10      4.6     19.3    =SUM(D10:D14)
11      10      11      3.2     14.7    =SUM(D11:D14)
12      11      12      3       11.5    =SUM(D12:D14)
13      12      13      5       8.5     =SUM(D13:D14)
14      13      14      3.5     3.5     =SUM(D14)
15      1       15      3       16.1    =SUM(D15:D18)
16      15      16      5.6     13.1    =SUM(D16:D18)
17      16      17      4.7     7.5     =SUM(D17:D18)
18      17      18      2.8     2.8     =SUM(D18)
19      6       19      0       11.7    =SUM(D19:D22)
20      19      20      3.8     8.8     =SUM(D20:D21)
21      20      21      5       5       =SUM(D21)
22      19      22      2.9     2.9     =SUM(D22)
23      8       23      4.4     4.4     =SUM(D23)

解决方法

使用 recursive CTE,您可以执行以下操作：

WITH RCTE AS 
(
    SELECT *,NULL S  FROM Table1
    UNION ALL
    SELECT t.*,COALESCE(r.S,r.SectionNumber) S FROM Table1 t
    INNER JOIN RCTE r ON r.FinalNode = t.InitialNode  
),CTE2 AS 
(
    SELECT S,SUM(Area) AS AreaCum FROM RCTE 
    GROUP BY S
)
SELECT t.*,COALESCE(c.AreaCum,t.Area) AreaCum FROM Table1 t
LEFT JOIN CTE2 c ON t.SectionNumber = c.S

SQLFiddle DEMO