在sql server中将日期范围拆分为每月一行

我有一个表有两列名为“from_date”和“to_date”的表

the table look like:-

我想要的结果如下： –

from_date            to_date   
-----------         ------------  
2013-11-25           2013-11-30
2013-12-01           2013-12-05

该日期从2013-11-25分为2013-11-30,另一个日期从2013-12-01分到2013-12-05 ……是否有可能像这样分开？

解决方法

这是闰年安全,并处理其他答案目前没有的日期范围.

DECLARE @d TABLE(from_date DATE,to_date DATE);

INSERT @d VALUES ('2013-11-25','2013-12-05');

;WITH n(n) AS 
(
  SELECT ROW_NUMBER() OVER (ORDER BY [object_id])-1 FROM sys.all_columns
),d(n,f,t,md,bp,ep) AS 
(
  SELECT n.n,d.from_date,d.to_date,DATEDIFF(MONTH,d.to_date),DATEADD(MONTH,n.n,DATEADD(DAY,1-DAY(from_date),from_date)),-1,1,from_date))))
 FROM n INNER JOIN @d AS d 
 ON d.to_date >= DATEADD(MONTH,n.n-1,d.from_date)
)
SELECT original_from_date = f,original_to_date = t,new_from_date = CASE n WHEN 0  THEN f ELSE bp END,new_to_date   = CASE n WHEN md THEN t ELSE ep END 
FROM d WHERE md >= n
ORDER BY original_from_date,new_from_date;

结果：

original_from_date   original_to_date   new_from_date   new_to_date
------------------   ----------------   -------------   -----------
2013-11-25           2013-12-05         2013-11-25      2013-11-30
2013-11-25           2013-12-05         2013-12-01      2013-12-05

SQLFiddle demo with longer date ranges and leap years

原文地址：https://www.jb51.cc/mssql/83985.html