php – 无法在codeigniter中从模型获取整个数据值

我有3张桌子

学生

id  s_name 
1     S1
2     S2

student_subject

id  s_id  subject
1    1      english
2    1      science
3    2      mathematics
4    2      poetry

老师

id t_id s_id
1   1    1
2   1    2

我正在尝试为老师制作一个仪表板,在那里他可以看到他下面的所有学生以及学生正在关注的科目.
我有老师的id(在t_id中)在控制器中,然后在模型中,从那里我从教师表中获取学生的ID(作为$s_id)并通过这个s_id我希望得到来自student table和student_subject表的详细信息.

我面临的问题是

1) In the model i am able to see all the details of student table but when i return the value to controller and then to view i get the detail of only 1 student.

2) In this model along with the student details i also wish to return the subjects that are under a particular student from student_subject table,however i don’t kNow how to return 2 values(i.e student details and subject details) from 1 model to 1 controller and then to view

我关注的代码是

调节器

public function dashboard($t_id)
        {
            $data['student_request'] = $this->student_model->student_detail($t_id);
            $this->load->view('teacher/dashboard_view',$data);
        }

模型

public function student_detail($t_id)
    {   
        $query = $this->db->query("SELECT * FROM teacher where t_id = $t_id");

        foreach ($query->result_array() as $row)
            {
                    $s_id = $row['s_id'];

                    $new_query = $this->db->query("SELECT * FROM student where id = $s_id");
                    $s = $new_query->result_array();
                    //print_r ($s); // just to check the data
                    return $s;
            }
    }

视图

PHP
foreach ($student_request as $row)
    {
        echo $row['s_name'];
    }
?>

如果有人能帮我解决这个问题,我真的很感激

最佳答案

保持控制器代码相同并更改模型和视图

模型

$this->db->select('
        teacher.s_id,student.s_name,student_subject.subject
    ');

$this->db->from('teacher');
$this->db->join('student','student.id = teacher.s_id');
$this->db->join('student_subject','student_subject.s_id = teacher.s_id');
$this->db->where('teacher.t_id',$t_id);

$query = $this->db->get();
if($query->num_rows() < 1)
    {
        return FALSE;
    }

    return $query->result();

视图

PHP if($student_request): ?>

    PHP foreach($student_request as $request): ?>

    PHP  
    echo $request->subject;
    echo $request->s_name;  

    ?>

    PHP  endforeach; ?>

    PHP endif; ?>