oracle 用密码复杂度

>sqlplus / as sysdba

sql*Plus: Release 11.2.0.3.0 Production on 星期一 3月 25 22:53:24 2013

copyright (c) 1982,2011,Oracle. All rights reserved.

连接到:

Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - Production

With the Partitioning,OLAP,Data Mining and Real Application Testing options

sql> @?/rdbms/admin/utlpwdmg.sql

转自：http://blog.itpub.net/23135684/viewspace-757083/

或者自定义脚本

-----------------------------------脚本如下-------------------------------------------- CREATE OR REPLACE FUNCTION PASSWORD_VERIFY_FUNCTION ( username varchar2,password varchar2,old_password varchar2) RETURN boolean IS n boolean; m integer; differ integer; isdigit boolean; ischar boolean; ispunct boolean; db_name varchar2(40); digitarray varchar2(20); punctarray varchar2(25); specialarray varchar2(14); chararray varchar2(52); i_char varchar2(10); simple_password varchar2(10); reverse_user varchar2(32); BEGIN digitarray:= '0123456789'; chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMnopQRSTUVWXYZ'; specialarray:= '~！@#$%^&*()_<>'; -- 校验密码长度至少为8位 IF length(password) < 8 THEN raise_application_error(-20001,'Password length less than 8'); END IF; -- 校验密码是否和用户名相同 IF NLS_LOWER(password) = NLS_LOWER(username) THEN raise_application_error(-20002,'Password same as or similar to user'); END IF; FOR i IN 1..100 LOOP i_char := to_char(i); if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN raise_application_error(-20005,'Password same as or similar to user name '); END IF; END LOOP; -- 校验密码是不是用户名的反序 FOR i in REVERSE 1..length(username) LOOP reverse_user := reverse_user || substr(username,i,1); END LOOP; IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN raise_application_error(-20003,'Password same as username reversed'); END IF; -- 校验密码是否是服务名 select name into db_name from sys.v$database; if NLS_LOWER(db_name) = NLS_LOWER(password) THEN raise_application_error(-20004,'Password same as or similar to server name'); END IF; FOR i IN 1..100 LOOP i_char := to_char(i); if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN raise_application_error(-20005,'Password same as or similar to server name '); END IF; END LOOP; -- 检查用户密码是否过于简单， -- 检查密码是否有列表中的关键字 -- 是否存在弱口令 IF NLS_LOWER(password) IN ('welcome1','database1','account1','user1234','password1','oracle123','computer1','abcdefg1','change_on_install') THEN raise_application_error(-20006,'Password too simple'); END IF; -- 检查密码是否为oracle simple_password := 'oracle'; FOR i IN 1..100 LOOP i_char := to_char(i); if simple_password || i_char = NLS_LOWER(password) THEN raise_application_error(-20007,'Password too simple '); END IF; END LOOP; -- 检验密码至少包含至少一个字母，一个数字,一个特殊字符 -- 1. 校验数字 isdigit:=FALSE; m := length(password); FOR i IN 1..10 LOOP FOR j IN 1..m LOOP IF substr(password,j,1) = substr(digitarray,1) THEN isdigit:=TRUE; GOTO findchar; END IF; END LOOP; END LOOP; IF isdigit = FALSE THEN raise_application_error(-20008,'Password must contain at least one digit,one character'); END IF; -- 2. 检验字符 <<findchar>> ischar:=FALSE; FOR i IN 1..length(chararray) LOOP FOR j IN 1..m LOOP IF substr(password,1) = substr(chararray,1) THEN ischar:=TRUE; GOTO endsearch; END IF; END LOOP; END LOOP; IF ischar = FALSE THEN raise_application_error(-20009,'Password must contain at least one \ digit,and one character'); END IF; -- 3. 检验特殊字符 <<findchar>> ischar:=FALSE; FOR i IN 1..length(specialarray) LOOP FOR j IN 1..m LOOP IF substr(password,1) = substr(specialarray,'Password must contain at least one special_char'); END IF; <<endsearch>> --检验密码和上一个密码至少有三个不同字符 -- IF old_password IS NOT NULL THEN differ := length(old_password) - length(password); differ := abs(differ); IF differ < 3 THEN IF length(password) < length(old_password) THEN m := length(password); ELSE m := length(old_password); END IF; FOR i IN 1..m LOOP IF substr(password,1) != substr(old_password,1) THEN differ := differ + 1; END IF; END LOOP; IF differ < 3 THEN raise_application_error(-20011,'Password should differ from the \ old password by at least 3 characters'); END IF; END IF; END IF; -- Everything is fine; return TRUE ; RETURN(TRUE); END; --------------------------------------------------------------------------------------

原文地址：https://www.jb51.cc/oracle/209050.html