微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

oracle 分析函数over

drop table test111;
create table test111(
name varchar2(10),
class number,
grade number

)
select * from test111;

insert into test111 values('a',1,23);
insert into test111 values('b',213);
insert into test111 values('bb',213);
insert into test111 values('bbb',null);
insert into test111 values('c',2123);
insert into test111 values('d',2);
insert into test111 values('e',2,223);
insert into test111 values('r',2233);
insert into test111 values('t',273);
insert into test111 values('y',3,237);
insert into test111 values('u',4,2543);

select name,class,grade,sum(grade)over (partition by class order by grade desc) from test111

select name,dense_rank()over(partition by class order by grade desc) mm from test111

select name,to_char(wm_concat(grade) over (partition by class order by grade)) from test111

select name,row_number() over (partition by class order by grade) from test111

http://www.jb51.cc/article/p-yjzzpqeh-wt.html

原文地址:https://www.jb51.cc/oracle/210918.html

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。

相关推荐