我有一个用逗号隔开多年的字符串.
例如2000,2001,2002,2005,2006,2007和2010.
我想将连续数字分组.
我的输出应该是2000-2003,2005-2007和2010.在Oracle存储过程中有没有办法做到这一点？
18:42:15 SYstem@dwal> l 1 with p as ( 2 select replace('2000,2007 and 2010',' and ',',') s,'[0-9]{4}' r from dual 3 ),ex as ( 4 select regexp_substr(s,r,1,level) as y 5 from p 6 connect by level <= regexp_count(s,r) 7 ),grp as ( 8 select connect_by_root(y) s,y 9 from ( select e1.y y,e2.y p from ex e1,ex e2 where e1.y - 1 = e2.y(+) ) 10 connect by prior y = p 11 start with p is null 12 ),agg as ( 13 select listagg(s||decode(max(y),s,null,'-'||max(y)),') within group (order by s) str 14 from grp group by s 15 ) 16* select regexp_replace(str,regexp_count(str,')) result from agg 18:42:16 SYstem@dwal> / RESULT ------------------------------ 2000-2002,2005-2007 and 2010 Elapsed: 00:00:00.02
版权声明：本文内容由互联网用户自发贡献，该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 dio@foxmail.com 举报，一经查实，本站将立刻删除。
