python-从pandas中获取上一行的值apply()函数

import pandas as pd

def greater_or_less(d):
    if d['current'] > d['prevIoUs']:
        d['result']="Greater"
    elif d['current'] < d['prevIoUs']:
        d['result']="Less"
    elif d['current'] == d['prevIoUs']:
        d['result']="Equal"
    else:
        pass
    return d

df=pd.DataFrame({'current':[1,2,2,8,7]})

# Duplicate the column with shifted values
df['prevIoUs']=df['current'].shift(1)

df['result']=""

df=df.apply(greater_or_less,axis=1)

结果是：

   current  prevIoUs   result
        1       NaN         
        2         1  Greater
        2         2    Equal
        8         2  Greater
        7         8     Less

然后,我将不再需要上一列.最后是：

   current   result
        1         
        2  Greater
        2    Equal
        8  Greater
        7     Less

如何在不添加额外列的情况下执行此操作？

我想做的是,知道如何从Greater_or_less函数中引用上一行的值.

解决方法:

使用diff()方法：

import pandas as pd
import numpy as np
df=pd.DataFrame({'current':[1,2,2,8,7]})
np.sign(df.current.diff()).map({1:"Greater", 0:"Equal", -1:"Less"})