python-如果条件失败,np.where()不执行任何操作

我有一个数据框示例：

       Created      Insert Time   MatchKey              In PrevIoUs    New Type
18593  2016-08-12   2018-02-19    LXGS090393APIN040640       No        New Existing
5517   2016-08-12   2018-02-19    LIN380076CI166203726       No        New Existing
2470   2018-02-12   2018-02-19    CI164414649APIN160672      No        New Existing
13667  2016-08-12   2018-02-19    LIN257400APIN015446       Yes        New Existing
10998  2016-08-12   2018-02-19    LXSV225786APIN158860      Yes        New Existing
20149  2016-08-12   2018-02-19    LIN350167APIN158284       Yes        New Existing
20143  2016-08-12   2018-02-19    LIN350167APIN161348       Yes        New Existing
30252  2016-08-12   2018-02-19    LXGS120737APIN153339      Yes        New Existing
12583  2016-08-09   2018-02-19    WIN556410APIN157186       Yes        New Existing
28591  2018-05-03   2018-02-19    CI195705185APIN009076      No        New Created

我想以某种方式替换“新类型”列中的值,如果条件失败,该函数将不执行任何操作：

current['New Type'] = np.where(current['In PrevIoUs']=='Yes','In PrevIoUs',pass)

但显然会导致语法错误,因为np.where()无法处理传递：

File "<ipython-input-9-7f68cda12cbe>", line 1
current['New Type'] = np.where(current['In PrevIoUs']=='Yes','In PrevIoUs',pass)

                                                                          ^
SyntaxError: invalid Syntax

有什么办法可以达到相同的目的？

解决方法:

仅返回该列而不是传递,这与条件为False时不执行任何操作相同：

current['New Type'] = np.where(current['In PrevIoUs']=='Yes','In PrevIoUs',current['New Type'] )

或者,您可以掩盖这些行：

current['New Type'] = current.loc[current['In PrevIoUs']=='Yes', 'In PrevIoUs']