首先,对于长篇解释感到抱歉.我在PHP中有两个数组.第一个数组是一个对象数组.第二个数组是一个数组数组.基本上,我想循环,并将对象与其匹配的数组合并,并返回一个合并的对象.
请参阅以下对象结构数组的print_r():
Array
(
[0] => stdClass Object
(
[gear] => helloworld
[status] => running
[started] => 40 Minutes Ago
[start] => index.js
[route] => 127.0.0.1:3000
[parameters] => Array
(
)
)
[1] => stdClass Object
(
[gear] => test
[status] => stopped
[started] =>
[start] => index.js
[route] =>
[parameters] => Array
(
)
)
[2] => stdClass Object
(
[gear] => test2
[status] => stopped
[started] =>
[start] => index.js
[route] =>
[parameters] => Array
(
[0] => first
[1] => second
[2] => third
)
)
)
请参阅以下数组结构数组的print_r():
Array
(
[0] => Array
(
[gear] => helloworld
[machine_id] => E6z5ekvQ
[created_by] => 10010
[modified_by] => 10010
[created] => 2011-09-22T16:30:11-07:00
[modified] => 2011-09-22T16:30:11-07:00
)
[1] => Array
(
[gear] => test
[machine_id] => E6z5ekvQ
[created_by] => 10010
[modified_by] => 10010
[created] => 2011-09-22T16:44:25-07:00
[modified] => 2011-09-22T16:44:25-07:00
)
[2] => Array
(
[gear] => test2
[machine_id] => E6z5ekvQ
[created_by] => 10010
[modified_by] => 10010
[created] => 2011-09-22T16:45:43-07:00
[modified] => 2011-09-22T16:45:43-07:00
)
)
所以基本上两者的匹配键都是齿轮.所以我们应该匹配第一个物体的齿轮,阵列中的第二个齿轮,并返回如下内容:
stdClass Object
(
[gear] => helloworld
[status] => running
[started] => 40 Minutes Ago
[start] => index.js
[route] => 127.0.0.1:3000
[parameters] => Array
(
)
[machine_id] => E6z5ekvQ
[created_by] => 10010
[modified_by] => 10010
[created] => 2011-09-22T16:30:11-07:00
[modified] => 2011-09-22T16:30:11-07:00
)
请注意,齿轮合并为物体的一个属性,显然齿轮不会出现两次.想法?
解决方法:
如果你可以通过齿轮或一些独特的值索引数组,那将会容易得多.
$indexed = array();
// create an array using 'gear' as the index
foreach($arrayValue as $value) {
$indexed[$value['gear']] = $value;
}
// loop over each object
foreach($objectArray as $obj) {
$value = $indexed[$obj->gear]; // find the corresponding array
foreach($value as $name => $val) {
$obj->$name = $val; // assign each array index/value pair to the object
}
}
如果可能的话,默认情况下让代码返回带索引的数组,可以删除第一个foreach循环.
希望有所帮助.
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