php – 从SQL中提取数据,并写入文本文件

我试图从sql中提取数据,然后将其写入文本文件.这样做,在某种程度上,但它只从表中读取1,其中读取test：test< br>在文本文件上.

I want to be able to pull all the data
from the table, and then post to the
text file in a list format such as
this…

    test:test
    test2:test2
    test3:test3

我需要找出我做错了什么.

<?PHP
$sql = MysqL_query("SELECT * FROM _$setprofile ORDER BY fc DESC");
while($row = MysqL_fetch_array($sql)){
$user = $row['user'];
$pass = $row['pass'];

$accounts = "$user:$pass<br>";

//Functionsss!
$file = "backups/$newcode.txt";
file_put_contents($file, $accounts);
}

echo "<a href=backups/$newcode.txt>TEST!</a>";
?>

解决方法:

file_put_contents()函数会覆盖整个文件 – 这就是为什么每次只能记录最后一条记录的原因.

您可以使用fopen()和fwrite().

虽然比构建一个大字符串并使用一次调用file_put_contents稍微复杂一点,但如果你有很多记录,这将不会耗尽内存.

<?PHP

$file = "backups/$newcode.txt";
$f = fopen($file, 'w'); // Open in write mode

$sql = MysqL_query("SELECT * FROM _$setprofile ORDER BY fc DESC");
while($row = MysqL_fetch_array($sql))
{
    $user = $row['user'];
    $pass = $row['pass'];

    $accounts = "$user:$pass<br>";
    // Or "$user:$pass\n" as @Benjamin Cox points out

    fwrite($f, $accounts);
}

fclose($f);

echo "<a href=backups/$newcode.txt>TEST!</a>";
?>