php – 警告：mysqli_real_escape_string()预计正好有2个参数,1给出……我做错了什么？

我尝试使用PHP 登录但我得到这个错误：警告：mysqli_real_escape_string()预计正好2个参数,1给出,我做错了什么？

<!doctype html>
<html lang"fi">
<head>
<link rel="icon" type='image/png' href='images/logo.png'>
<title>
asd
</title>
<link href="css/styles.css" type="text/css" rel="stylesheet">
</head>
<body>
<!--reg alkaa-->
<form action="register.PHP" method="post">
<p><input type="text" name="username" placeholder="Username">
<p><input type="email" name="email" placeholder="Email">
<p><input type="password" name="pass" placeholder="Password">
<p><input type="password" name="pass1" placeholder="Password">
<p><input type="submit" name="submit" value="Register">
</form>
<?PHP

if(isset($_POST['submit']))
{
$username = MysqLi_real_escape_string($_POST['username']);
$pass = MysqLi_real_escape_string($_POST['pass']);
$pass1 = MysqLi_real_escape_string($_POST['pass1']);
$email = MysqLi_real_escape_string($_POST['email']);
if($username && $pass && $pass1 && $email)
{
if($pass==$pass1)
{
    $connect = MysqL_connect("MysqL.example.com","username","password");
    MysqL_select_db("my_database");
    $query = MysqL_query("INSERT INTO users VALUES('$username','$pass','$email');");
    echo "You have been registered.";
}
else
{
    echo "Password must match.";
}
}
else
{
echo "All fields are required.";
}
}
 ?>
<!--reg end-->
<Center>
<a href="index.PHP">
<h1>
asd
</h1>
</center>
<div id="main">
<h3>
 <div class="menu"> <a href="index.PHP">Etusivu</a> &bullet; 
 <a                                       </div>
</h3>
</div>
<div class="jonne"> 
</div>
<script src="javascript/jquery.js"></script>
</body>
</html>

我使用000webhost,这是我第一次在线使用MysqL 数据库.

解决方法:

你正在混合MysqLi和MysqL 函数.

如果你正在使用MysqL 函数,那么改为MysqLi_real_escape_string($your_variable);使用

$username = MysqL_real_escape_string($_POST['username']);
$pass = MysqL_real_escape_string($_POST['pass']);
$pass1 = MysqL_real_escape_string($_POST['pass1']);
$email = MysqL_real_escape_string($_POST['email']);

如果您使用MysqLi_ *函数,则必须将您与数据库的连接包含在mysqli_real_escape function中：

$username = MysqLi_real_escape_string($your_connection, $_POST['username']);
$pass = MysqLi_real_escape_string($your_connection, $_POST['pass']);
$pass1 = MysqLi_real_escape_string($your_connection, $_POST['pass1']);
$email = MysqLi_real_escape_string($your_connection, $_POST['email']);

注意：使用MysqLi_ *函数,因为不推荐使用MysqL.有关信息,请阅读mysqli_ *

php – 警告：mysqli_real_escape_string()预计正好有2个参数,1给出……我做错了什么？

相关推荐