所以我写了一个函数,在一个数组中深入搜索两个级别的密钥和子密钥对.基本上它正在寻找key [‘subkey’],如果找到它,则返回key [‘subkey’].
我正在寻找的是一种以真正递归的方式执行此操作的方法,并根据需要搜索多个级别,直到它到达数组的末尾并被强制返回false,或者找到值并返回它.
我在PHP上完全是新手,我用谷歌搜索了几个小时没有结果.任何指向正确的方向将不胜感激.
这是功能:
function searchArray($array, $key, $subkey) {
foreach ($array as $item){
if (is_array($item) && isset($item[$key]) && isset($item[$key][$subkey])){
return $item[$key][$subkey];
} else {
foreach ($item as $subitem){
if (is_array($subitem) && isset($subitem[$key]) && isset($subitem[$key][$subkey])){
return $subitem[$key][$subkey];
}
}
}
}
}
样本数组:
"locales" => array(
"America" => array(
"locations" => array(
"us" => array(
"title" => "United States",
"lang" => "en_US",
),
"gl" => array(
)
)
),
"Europe" => array(
"locations" => array(
"at" => array(
"title" => "Österreich",
"lang" => "de_DE",
),
"fr" => array(
"title" => "France",
"lang" => "fr_FR",
),
"de" => array(
"title" => "Deutschland",
"lang" => "de_DE",
),
"it" => array(
"title" => "Italy",
"lang" => "it_IT",
),
"uk" => array(
"title" => "United Kingdom",
"lang" => "en_GB",
)
)
),
"Africa" => array(
"locations" => array(
"za" => array(
"title" => "Südafrika",
"lang" => "en_ZA",
)
)
),
"Asia & Pacific" => array(
"locations" => array(
"au" => array(
"title" => "Australia",
"lang" => "en_AU",
),
"cn" => array(
"title" => "中国",
"lang" => "zh_CN",
),
"hk" => array(
"title" => "香港",
"lang" => "zh_CN",
),
"jp" => array(
"title" => "日本",
"lang" => "jp_JP",
),
"kr" => array(
"title" => "한국",
"lang" => "ko_KR",
)
)
)
)
调用searchArray($siteOptions [‘locales’],’us’,’lang’)应返回’en_US’.
解决方法:
function walk($array, $key, $option) {
if( !is_array( $array)) {
return false;
}
foreach ($array as $k => $v) {
if($k == $key && is_array($v) && isset($v[$option])){
return $v[$option];
}
$data = walk($v, $key, $option);
if($data != false){
return $data;
}
}
return false;
}
echo walk($array, 'jp', 'lang');
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