使用Google PHP SDK的YouTube API – 响应为JSON

对于我最新的项目,我需要将YouTube搜索结果作为JSON字符串.我试图从here 修改官方Samples的代码,以便整个响应数组作为JSON返回,但JSON输出只包含一个结果,只有两个结果的标记

{“etag”:”\”bvxF-DWHx1toJotsdJBeCm43SLs/Ti9GPWl-tTk2fzo_W4M7px11bPY\””,”eventId”:null,”kind”:”youtube#searchListResponse”,”nextPagetoken”:”CBkQAA”,”prevPagetoken”:null,”visitorId”:null}

这就是我的代码：

<?PHP
header('Cache-Control: no-cache, must-revalidate');
header('Content-type: application/json');
if ($_GET['q'] && $_GET['maxResults']) {
require_once 'Google/Client.PHP';
require_once 'Google/Service/YouTube.PHP';
$DEVELOPER_KEY = 'not gonna reveal my key ;) ';
$client = new Google_Client();
$client->setDeveloperKey($DEVELOPER_KEY);
$youtube = new Google_Service_YouTube($client);
try 
{
    $searchResponse = $youtube->search->listSearch('id,snippet', array(
        'q' => $_GET['q'],
        'maxResults' => $_GET['maxResults'],
    ));
    print_r(json_encode($searchResponse));
} 
catch (Google_ServiceException $e) {
    $htmlBody .= sprintf('<p>A service error occurred: <code>%s</code></p>',
    htmlspecialchars($e->getMessage()));
} 
catch (Google_Exception $e) {
    $htmlBody .= sprintf('<p>An client error occurred: <code>%s</code></p>',
    htmlspecialchars($e->getMessage()));
    }
}
?>

最后我会喜欢有类似的东西

    {
 "kind": "youtube#searchListResponse",
 "etag": "\"bvxF-DWHx1toJotsdJBeCm43SLs/vL7IQMNuL84nujDqKdOtwOPpBkc\"",
 "nextPagetoken": "CAIQAA",
 "pageInfo": {
  "totalResults": 203164,
  "resultsPerPage": 2
 },
 "items": [
  {
   "kind": "youtube#searchResult",
   "etag": "\"bvxF-DWHx1toJotsdJBeCm43SLs/m4lAJ1Qx-hvZpw4Uc9qSo_rqy5o\"",
   "id": {
    "kind": "youtube#video",
    "videoId": "UyI4v5sxT54"
   },
   "snippet": {
    "publishedAt": "2014-04-14T10:21:21.000Z",
    "channelId": "UCpDJl2EmP7Oh90Vylx0dZtA",
    "title": "BORGORE & SIKDOPE - Unicorn Zombie Apocalypse (Original Mix)",
    "description": "BORGORE teams up with SIKDOPE to bring you the main stage rocker that is Unicorn Zombie Apocalypse. Grab your copy Now : http://btprt.dj/1hFUQhP ...",
    "thumbnails": {
     "default": {
      "url": "https://i.ytimg.com/vi/UyI4v5sxT54/default.jpg"
     },
     "medium": {
      "url": "https://i.ytimg.com/vi/UyI4v5sxT54/mqdefault.jpg"
     },
     "high": {
      "url": "https://i.ytimg.com/vi/UyI4v5sxT54/hqdefault.jpg"
     }
    },
    "channelTitle": "SpinninRec",
    "livebroadcastContent": "none"
   }
  },
  {
   "kind": "youtube#searchResult",
   "etag": "\"bvxF-DWHx1toJotsdJBeCm43SLs/4LQaEODdVEec6exNA21SnYJAeOU\"",
   "id": {
    "kind": "youtube#video",
    "videoId": "CPXv392pc9k"
   },
   "snippet": {
    "publishedAt": "2014-05-16T23:00:00.000Z",
    "channelId": "UCpDJl2EmP7Oh90Vylx0dZtA",
    "title": "Borgore & Sikdope - Unicorn Zombie Apocalypse (Official Music Video)",
    "description": "Borgore & Sikdope present Unicorn Zombie Apocalypse (Official Music Video). Download your copy on Beatport HERE : http://btprt.dj/1hFUQhP English ...",
    "thumbnails": {
     "default": {
      "url": "https://i.ytimg.com/vi/CPXv392pc9k/default.jpg"
     },
     "medium": {
      "url": "https://i.ytimg.com/vi/CPXv392pc9k/mqdefault.jpg"
     },
     "high": {
      "url": "https://i.ytimg.com/vi/CPXv392pc9k/hqdefault.jpg"
     }
    },
    "channelTitle": "SpinninRec",
    "livebroadcastContent": "none"
   }
  }
 ]
}

解决方法:

问题是您正在尝试对使用PHP客户端库时收到的响应对象进行JSON编码.它不是Youtube API返回的原始JSON对象(以及您要编码的内容).

如果你var_dump($searchResponse);你会看到它说Google_Service_YouTube_SearchListResponse对象

你想通过在模型上调用toSimpleObject来json_encode你得到的“simpleObject”,如：

json_encode($searchResponse->toSimpleObject());

使用Google PHP SDK的YouTube API – 响应为JSON

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