php – SQL Complexed Join

我想通过下表为客户列出购买记录.

Table: Invoice
----------------------

invID | cusID | total
----------------------
1     | 1     | 10.5


Table: Invoice Item
--------------------

invID | prodID
---------------
1     | 1     
1     | 3

现在我想输出为一行像这样:(或在PHP提取的行表中)

invID | cusID | prodID | total
-------------------------------
1     | 1     | 1, 3   | 10.5

我试过了什么：

SELECT i.*, ii.prodID FROM invoice i, invoiceitem ii WHERE cusID = '1' AND i.invID = ii.invID
Result:

invID | cusID | prodID | total
-------------------------------
1     | 1     | 1      | 10.5
1     | 1     | 3      | 10.5

解决方法:

我认为这对你有用.没有测试过,所以某处可能会有一个小错字,但这个概念应该有效.

SELECT i.invID, i.cusID, GROUP_CONCAT(ii.prodID) `prodID`, i.total
FROM invoice i
INNER JOIN invoiceitem ii ON i.invID = ii.invID
GROUP BY i.invID