PHP：将字符串转换为多维数组

我试图将字符串转换为数组,但是,当字符串包含括号中的项目时,我想创建多维数组.

例如,如果传递的字符串：(Mary Poppins)Umbrella(Color Yellow)

我想创建一个如下所示的数组：

Array ( [0] => Array ( [0] => mary [1] => poppins) [1] => umbrella [2] => Array ( [0] => color [1] => yellow) )

我能够通过以下方式将数据放入数组中：

preg_match_all('/\(([A-Za-z0-9 ]+?)\)/', stripslashes($_GET['q']), $subqueries); 

但我无法将项目放在多维数组中.

有任何想法吗？

解决方法:

使用一些PHP-Fu：

$string = '(Mary Poppens) Umbrella (Color Yellow)';
$array = array();
preg_replace_callback('#\((.*?)\)|[^()]+#', function($m)use(&$array){
    if(isset($m[1])){
        $array[] = explode(' ', $m[1]);
    }else{
        $array[] = trim($m[0]);
    }
}, $string);
print_r($array);

输出：

Array
(
    [0] => Array
        (
            [0] => Mary
            [1] => Poppens
        )

    [1] => Umbrella 
    [2] => Array
        (
            [0] => Color
            [1] => Yellow
        )

)

Online demo

_{Note that you need PHP 5.3+ since I’m using an anonymous function.}

兼容吗？

$string = '(Mary Poppens) Umbrella (Color Yellow)';

preg_match_all('#\((.*?)\)|[^()]+#', $string, $match, PREG_SET_ORDER);

foreach($match as $m){
    if(isset($m[1])){
        $array[] = explode(' ', $m[1]);
    }else{
        $array[] = trim($m[0]);
    }
}

print_r($array);

Online demo

_{Tested on PHP 4.3+}