php – 在Laravel项目中为注释创建Like系统时遇到问题

我正在使用Laravel创建一个项目.用户可以喜欢评论.我想显示一个“喜欢”按钮,以便用户可以喜欢评论,如果用户已经喜欢评论,我希望该按钮“不像”,这样用户可以不同于喜欢的评论

在我的数据库中,我有一个喜欢的表：

| id | user_id | comment_id |

我喜欢的模型看起来像这样：

class Like extends \Eloquent {

    protected $fillable = ['user_id', 'comment_id'];
    protected $table = 'likes';

    public function owner()
    {
        return $this->belongsTo('Acme\Users\User', 'user_id');
    }
}

评论模型如下所示：

class Comment extends \Eloquent {

    protected $fillable = ['user_id', 'post_id', 'body'];
    protected $table = 'comments';

    public function owner()
    {
        return $this->belongsTo('Acme\Users\User', 'user_id');
    }
    public function likes()
    {
        return $this->hasMany('Acme\Likes\Like');
    }
}

用户模型：

class User extends Eloquent {

    public function comments()
    {
        return $this->hasMany('Acme\Comments\Comment');
    }
    public function likes()
    {
        return $this->hasMany('Acme\Likes\Like');
    }

}

喜欢控制器：

class LikesController extends \BaseController {

use CommanderTrait;

/**
 * Like a comment
 * @return Response
 */
public function commentLike()
{
// using a command bus. Basically making a post to the likes table assigning user_id and comment_id then redirect back
    extract(Input::only('user_id', 'comment_id'));
    $this->execute(new CommentLikeCommand($user_id, $comment_id));

    return Redirect::back();
}
public function unlike()
{
    $like = new Like;
    $user = Auth::user();
    $id = Input::only('comment_id');
    $like->where('user_id', $user->id)->where('comment_id', $id)->first()->delete();
    return Redirect::back();
}
}

在我看来,我可以通过$comment获得评论,我可以通过$comment->获得喜欢：喜欢：

@foreach($post->comments as $comment)
<div class="user-comment">
    <p class="comment">
        {{ $comment->owner->first_name }}&nbsp;{{ $comment->owner->last_name }}&nbsp;{{ $comment->body }}
    </p>

    <div class="com-details">
<!-- how long ago the comment was posted -->
    <div class="com-time-container">
        &nbsp;{{ $comment->created_at->diffForHumans() }} ·
    </div>

<!-- HERE IS WHERE I WANT THE LIKE AND UNLIKE BUTTONS TO disPLAY -->
    @if ($comment->likes->owner->id === $currentUser->id)
        {{ Form::open(['route' => 'like']) }}
            {{ Form::hidden('user_id', $currentUser->id) }}
            {{ Form::hidden('comment_id', $comment->id) }}
            <button type="submit" class="com-like">Like</button>
        {{ Form::close() }}
    @else
        {{ Form::open(['route' => 'unlike']) }}
            {{ Form::hidden('user_id', $currentUser->id) }}
            {{ Form::hidden('comment_id', $comment->id) }}
            <button type="submit" class="com-like">Unlike</button>
        {{ Form::close() }}
    @endif
<!-- how many users like this comment -->
    <span class="likes"> · {{ $comment->likes->count() }}</span>
    </div>
</div><!--user-comment end-->
@endforeach

我试图设置一个if语句,以查看当前用户是否喜欢该状态,但我不知道如何做到这一点？如果用户还不喜欢评论,我想要显示“喜欢”按钮.如果用户喜欢评论,我希望显示“不同”按钮.我想我可以说@if($comment-> likes-> owner-> id === $currentUser-> id)但我得到了Undefined属性.我该怎么做呢？

解决方法:

$comment-> likes是Like对象的集合.要访问所有者属性,您需要迭代该集合.

但是,另一种选择是使用Collection上的可用方法来执行您需要的操作：

@if (in_array($currentUser->id, $comment->likes->lists('user_id')))

$comment-> likes-> lists(‘user_id’)将返回Comment的Likes集合中所有user_id值的数组. in_array()将检查$currentUser-> id是否在该数组中.