我的字符串函数时间戳
// Timestamp To String
function time2string($time) {
// DAYS
$d = floor($time/86400);
if ($d > 0) { $_d = $d.($d > 1 ? ' days' : ' day'); }
else { $_d = ""; }
// HOURS
$h = floor(($time-$d*86400)/3600);
if ($h > 0) { $_h = $h.($h > 1 ? ' hours' : ' hour'); }
else { $_h = ""; }
// MINUTES
$m = floor(($time-($d*86400+$h*3600))/60);
if ($m > 0) { $_m = $m.($m > 1 ? ' minutes' : ' minute'); }
else { $_m = ""; }
// SECONDS
$s = $time-($d*86400+$h*3600+$m*60);
if ($s >0) { $_s = $s.($s > 1 ? ' seconds' : ' second'); }
else { $s = ""; }
$time_str = $_d.' '.$_h.' '.$_m.' '.$_s;
return $time_str;
}
time2string(22500)
6 hours 15 minutes
期望的输出
> 1秒
> 1分1秒
> 1小时,1分钟和1秒
> 1天,1小时,1分钟和1秒
解决方法:
我完全改变了第一篇文章.我想摆脱所有的数学处理,所以我决定使用DateTime对象……毕竟diff()非常适合这个任务.
function time2string($time) {
if($time==0){return '0 seconds';}
$t1=new DateTime();
$t2=new DateTime("+$time seconds");
$diff=$t1->diff($t2);
$units=['days'=>'day','h'=>'hour','i'=>'minute','s'=>'second']; // nominate units
foreach($units as $k=>$v){
if($diff->$k!=0){$result[]=$diff->$k.' '.$v.($diff->$k>1?'s':'');} // store non-zero strings
}
if(sizeof($result)==1){
return $result[0]; // return single element
}else{
$last=array_splice($result,-1); // remove last element from $a and store separately
return implode(', ',$result)." and {$last[0]}"; // return with correct delimiters
}
}
echo time2string(122510); // output: 1 day, 10 hours, 1 minute and 50 seconds
echo time2string(0); // output: 0 seconds
echo time2string(1); // output: 1 second
echo time2string(9199800); // output: 106 days, 11 hours and 30 minutes
echo time2string(69206400); // output: 801 days
echo time2string(3599); // output: 59 minutes and 59 seconds
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