php – Symfony3中带有VichUploader包的数据夹具

一个基本的Symfony 3应用程序安装并配置了VichUploader bundle,并带有一个用于上传文件的实体.

如何在我的ORM数据夹具中将文件附加到此实体？

有一个 question for this problem in Symfony 2,我已经尝试过该代码.夹具加载时没有错误,但“上传”文件未复制到其最终目的地.

我可以手动执行此操作,我的最新尝试如下所示：

<?PHP
// src/AppBundle/DataFixtures/ORM/LoadCourseData.PHP

namespace AppBundle\DataFixtures\ORM;

use Doctrine\Common\DataFixtures\OrderedFixtureInterface;
use Doctrine\Common\DataFixtures\AbstractFixture;
use Doctrine\Common\Persistence\ObjectManager;
use Symfony\Component\HttpFoundation\File\UploadedFile;
use Symfony\Component\HttpFoundation\File\MimeType\MimeTypeGuesser;
use AppBundle\Entity\Course;

class LoadCourseData extends AbstractFixture implements OrderedFixtureInterface
{
    public function load(ObjectManager $manager)
    {
        $course = new Course();
        $course->setName('How to make data fixtures in Symfony lol')
            ->setAuthor($this->getReference('admin-user'))
            ->setSummary('You\'ll kNow when I kNow!')
            ->setLicense($this->getReference('cc-by'))
            ->setDifficulty(1);

        // Persist to generate slug (to be used for uploads)
        $manager->persist($course);

        // Attach file

        // I copy it to a temporary directory as per the Symfony2 answer
        copy(__DIR__.'/../Files/kitten.jpg', '/tmp/kitten.jpg');

        // These are filled in for completeness
        $mimetype = MimeTypeGuesser::getInstance()->guess('/tmp/kitten.jpg');
        $size     = filesize('/tmp/kitten.jpg');

        // Create a new UploadedFile
        $file = new UploadedFile('/tmp/kitten.jpg', 'kitten.jpg', $mimetype, $size, null, true);

        // I have to move it manually?
        // Plus how can I take advantage of the VichUploader namer?
        $file->move(__DIR__.'/../../../../web/img/upload/course/');

        // Apply to entity
        $course->setimageFile($file);

        // Persist
        $manager->persist($course);
        $manager->flush();
    }

    public function getorder()
    {
        return 4;
    }
}

我的解决方案仍然需要大量的工作！我吠叫错了树吗？

>上传路径已在config.yml中定义.我应该从那里访问它们或将它们转换为参数
>需要更多错误检查和异常抛出
>文件被复制到目标但文件名错误,因为它没有使用配置的VichUploader命名符
>它应该住在其他地方,可能作为服务？

解决方法:

我发现GitHub上的VichUploader文档不是很好,所以我建议你使用Symfony文档：
http://symfony.com/doc/current/controller/upload_file.html

我在src / AppBundle下创建了一个FileUploader.PHP,如下所示：

<?PHP

// src/AppBundle/FileUploader.PHP
namespace AppBundle;

use Symfony\Component\HttpFoundation\File\UploadedFile;

class FileUploader
{
    private $targetDir;

    public function __construct($targetDir)
    {
        $this->targetDir = $targetDir;
    }

    public function upload(UploadedFile $file, $path, $name)
    {
        $fileName = $name.'.'.$file->guessExtension();

        $file->move($this->targetDir.$path, $fileName);

        return $fileName;
    }
}

这允许您指定文件,路径和名称.

然后在你的app / config / service.yml文件中添加它以引用它：

services:
  app.attachment_uploader:
      class: AppBundle\FileUploader
      arguments: ['%document_directory%']

然后,您需要在app / config / parameters.yml文件中指定％document_directory％：

parameters:
...
    document_directory: documents

在我的例子中,上面的’documents’文件夹位于web文件夹下,因此路径为’web / documents’.我想把所有东西都存放在同一个地方.

然后我在任何控制器中使用FileUploader,如下所示：

...
->add('catalog', FileType::class, array(            // Docs
        'label' => 'Catalog Course Description ',
        'required' => false,
        'attr' => array(
                'accept' => 'image/*,application/pdf,text/plain,application/msword',
                'onchange' => "checkFileSize('form_catalog')"
        ),
))
...

$file = $form->get("catalog")->getData();
$fileName = $this->get('app.attachment_uploader')->upload( $file,
        '/'.$pet->getStudent()->getBanId(),
        $pet->getCourse()->getCorTitle().'_'.'Catalog_Course_Desc'
...

$att_cat->setDocument($fileName);
$em->persist($att_cat);
$em->flush();

在上面的代码中,我得到了“目录”文件按钮数据,这是文件.然后调用’upload’方法指定文件和路径和文件名参数.然后保持实体($att_cat).

以上使用非常简单.

php – Symfony3中带有VichUploader包的数据夹具

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