php – Laravel不可能在哪里查询

我正在研究某些产品的过滤器.我有大部分工作但是我遇到了一个不可能的where子句的错误.

该表包含单个产品的多个行,我尝试匹配每个产品的多个条件,这会导致它失败.

如果您对此有意见,或者可能是解决此问题的方法,我将非常感激.

数据库表如下所示：

    --------------------------------------------
    |id | FilterKey | filterValue | product_id |
    --------------------------------------------
    |1  | Colour    | GunMetal    | 1          |
    |2  | Colour    | Silver      | 1          |
    |3  | Size      | 750cc       | 1          |
    |4  | Size      | 1000cc      | 1          |
    |5  | Colour    | Red         | 2          |
    |6  | Colour    | Blue        | 2          |
    |7  | Size      | 750cc       | 2          |
    |8  | Size      | 1000cc      | 2          |
    --------------------------------------------

过滤器看起来像这样：

public function scopeFilterProduct($query, $filters)
{
    $this->filters = $filters;
    if (count ($this->filters) === 1 && isset($this->filters[0]))
    {
        return $query;
    }
    $query->join('product_filters', 'products.id', '=', 'product_filters.product_id')->Where(function($query){
        foreach ($this->filters as $filter => $vals)
        {
            $this->filter = $filter;
            $this->vals = $vals;
            $query->Where(function ($query){

                $query->Where('filterKey', $this->filter); 

                $query->Where(function($query){
                    foreach ($this->vals as $val){

                        $query->orWhere('filterValue', $val); 
                    }
                    $this->vals = null;
                });

            });
            $this->filter = null;
        };
    }); 
    return $query;
}

然后输出以下sql语句：

select
  distinct
    `products`.`id`
  , `product_id`
from
 `products`
inner join
 `product_filters`
on
 `products`.`id` = `product_filters`.`product_id`
where 
     (
         (`filterKey` = 'Colour' and (`filterValue` = 'gunMetal'))
       and
         (`filterKey` = 'Size' and (`filterValue` = '750cc'))
     )
     and
       `products`.`deleted_at` is null

如果选中,如屏幕截图所示,则页面上只应显示“产品一”.

解决方法:

你认为你添加的范围是错误的.在我看来,即使你的数据库结构也不正确.这是我如何构建这个：

过滤表

该模型将包含所有过滤器值.例如,颜色,大小等.以下是过滤表的结构：

-----------------
|id | name      |
-----------------
|1  | Colour    |
|2  | Size      |
-----------------

所以你雄辩的模型会变成这样的：

class Filter extends Model
{
    protected $fillable = ['id', 'name'];

    public function products()
    {
        return $this->belongsToMany(Product::class, 'products_filters');          
    } 
}

产品表

您的产品型号变为：

class Product extends Model
{
    public function filters()
    {
        return $this->belongsToMany(Filter::class, 'products_filters');          
    } 
}

products_filters表

完成上述更改后,以下是表格的结构：

--------------------------------------------
|id | filter_id | filterValue | product_id |
--------------------------------------------
|1  | 1         | GunMetal    | 1          |
|2  | 1         | Silver      | 1          |
|3  | 2         | 750cc       | 1          |
|4  | 2         | 1000cc      | 1          |
|5  | 1         | Red         | 2          |
|6  | 1         | Blue        | 2          |
|7  | 2         | 750cc       | 2          |
|8  | 2         | 1000cc      | 2          |
--------------------------------------------

现在您只需查询过滤器表,然后获取所有过滤器的关联产品.之后,您只需编译一个独特产品列表.

Unqiue产品基于选定的过滤器.

$ids = [];
$products = new \Illuminate\Support\Collection();

foreach($filters as $filter) {
    foreach($filter->products as $product) {
        if(!in_array($product->id, $ids)) {
            $ids[] = $product->id;
            $products->push($product);
        }
    }
}

return view('results', compact('products'));

在您看来,您需要写：

@foreach($products as $product)
// Your product block HTML
@endforeach