MySQL POINT字段的PHP数据类型

我创建了一个 MySQL表,其中一个字段的类型为POINT,用于存储lat,lon坐标(例如：36.6294654 -93.1725982).

我收到错误,提交表单,我认为这是由于数据类型不匹配造成的.

sqlSTATE[22003]: Numeric value out of range: 1416 Cannot get geometry object from data you send to the GEOMETRY field

我的理解是POINT应该有示例的格式(我也尝试过lat,lon).我认为问题是空间将变量转换为STRING.

我错过了什么吗,在这里？

这是我的PHP 代码连接到数据库并插入记录.

// use google's geocoding service to transform an address into lat/lon coordinates (https://developers.google.com/maps/documentation/geocoding/)
$json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?address=' . urlencode($street) . ',+' . urlencode($city) . ',+' . urlencode($state) . ',+' . urlencode($zip) . '&key=YOUR_API_KEY');
$json = json_decode($json, true);
$latlon = $json['results'][0]['geometry']['location']['lat'] . ' ' . $json['results'][0]['geometry']['location']['lng'];
try {
    $dbh = new PDO('MysqL:host=someserver;port=someport;dbname=somedatabase', 'someusername', 'somepassword', array(PDO::ATTR_PERSISTENT => true));
    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $sql = 'INSERT INTO Venues (Name, Street, City, State, Zip, Country, TimeZone, LatLon, Phone, Email, Website, Host, Notes) VALUES (:name, :street, :city, :state, :zip, :country, :timezone, :latlon, :phone, :email, :website, :host, :notes)';
    $stmt = $dbh->prepare($sql);
    $stmt->execute(array(":name" => $name, ":street" => $street, ":city" => $city, ":state" => $state, ":zip" => $zip, ":country" => $country, ":timezone" => $timezone, ":latlon" => $latlon, ":phone" => $phone, ":email" => $email, ":website" => $website, ":host" => $host, ":notes" => $notes));
    if ($stmt->rowCount() == 1) {
        echo '<p>"' . $name . '" creation succeeded.</p>';
    } else {
        echo '<p>"' . $name . '" creation Failed.</p>';
    }
    $stmt->setFetchMode(PDO::FETCH_ASSOC);
    $dbh = null;
}
catch(PDOException $e) {
    echo $e->getMessage();
}

或者,我可以只有单独的lat和lon字段,但我想练习msyql的内置几何功能.

编辑…

按照this answer的建议,我用POINT()包围了$latlon.但是,它没有改变结果.

编辑2 …

这是表结构,以防万一看起来不正确.

VenueKey    int(11)
Name        varchar(255)
Street      varchar(255)
City        varchar(255)
State       varchar(2)
Zip         varchar(10)
Country     varchar(2)
TimeZone    varchar(20)
LatLon      point
Phone       varchar(20)
Email       varchar(255)
Website     varchar(255)
Host        varchar(255)
Notes       text

解决方法:

这应该可以解决您的问题：

$latlng = 'POINT(' . $json['results'][0]['geometry']['location']['lat']. " " . $json['results'][0]['geometry']['location']['lng']. ')';

然后使用PointFromText包装你的：latlon：

$sql = 'INSERT INTO Venues (Name, Street, City, State, Zip, Country, TimeZone, LatLon, Phone, Email, Website, Host, Notes) VALUES (:name, :street, :city, :state, :zip, :country, :timezone, PointFromText(:latlon), :phone, :email, :website, :host, :notes)';

MySQL POINT字段的PHP数据类型

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