php – 将变量值从库传递到控制器,然后在CI 3.0中查看

我正在尝试将变量值从库函数传递给控制器​​,然后查看以获取输出.

对于我的库代码：

<?PHP                                                                                   

defined('BASEPATH') OR exit('No direct script access allowed');

/**
 * @description : Library to access MyOperator Public API
 */
Class My_Operator extends Admin_controller{

    protected $developers_url = 'https://developers.myoperator.co/';
    protected $token = 'XXXXXXXXX';

    function __construct() {

    }

    public function run() {
        # request for Logs
        $url = $this->developers_url . 'search';
        $fields = array("token" => $this->token);
        $result = $this->_post_api($fields, $url);

        $this->log("result");
        $this->log($result);
    }

    private function _post_api(Array $fields, $url) {
        try {
            $ch = curl_init();
            curl_setopt($ch, CURLOPT_URL, $url);
            curl_setopt($ch, CURLOPT_TIMEOUT, 30);
            curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
            curl_setopt($ch, CURLOPT_CUSTomrEQUEST, 'POST');
            curl_setopt($ch, CURLOPT_POSTFIELDS, $fields);
            $result = curl_exec($ch);
        } catch (Exception $e) {
            return false;
        }
        $this->log("url");
        $this->log($url);
        $this->log("fields");
        $this->log($fields);
        curl_close($ch);
        if ($result)
            return $result;
        else
            return false;
    }

    private function log($message) {
        print_r($message);
        echo "\n";
    }

}

扩展从核心文件扩展Admin_controller.

我的控制器代码是：

<?PHP
defined('BASEPATH') OR exit('No direct script access allowed');
class Myoperator extends Admin_controller
{

    public function __construct()
    {
        parent::__construct();
        //$this->load->model('myoperator_model');
    }

    public function index()
   {
       try {
           $this->load->library('my_operator');  
           $data = $this->my_operator->run();
       } catch (Exception $e) {
           var_dump($e->getMessage());
       }

       $this->load->view('admin/myoperator/view', $data);
   }
}

我的观看代码是：

<?PHP init_head(); ?>
    <div id="wrapper">
        <div>
            <?PHP
                echo $this->MY_Operator->run();
            ?>
        </div>
    </div>
<?PHP init_tail(); ?>

</body>
</html>

我不会得到理想的输出.
为此,我评论道：

codeigniter data passing controller->library->view

Pass data from library to controller and then to view in CodeIgniter 2

passing parameter from view to library and return after process Code igniter

当我运行此代码时出现错误

This page isn’t working localhost is currently unable to handle this
request. HTTP ERROR 500

根据我的理解,如果服务器配置有任何问题,则会出现此错误,但同一应用程序中的其他页面运行完美.

编辑：
以前的错误已经解决,一些链接问题,但是当我扩展该类时,会出现新的错误：

Unable to locate the specified class: Session.PHP

是否可以将核心文件类扩展到库类？

请帮我解决这个问题.任何形式的帮助表示赞赏.提前致谢.

解决方法:

解决了我的问题,只是忘了在Myoperator控制器文件中包含Admin_controller文件.

这是我更新的代码：

<?PHP
defined('BASEPATH') OR exit('No direct script access allowed');
require APPPATH. 'core/Admin_controller.PHP'; //forgot this line of code
class Myoperator extends Admin_controller
{

    public function __construct()
    {
        parent::__construct();
        //$this->load->model('myoperator_model');
    }

    public function index()
   {
       try {
           $this->load->library('my_operator');  
           $data = $this->my_operator->run();
       } catch (Exception $e) {
           var_dump($e->getMessage());
       }

       $this->load->view('admin/myoperator/view', $data);
   }
}