php – SQL SELECT仅包含两个不同表中列的MAX值的行

我的两个表设置如下：

表格1

+------+---------+--------------------------------------+
| id   | tail    | content                              |
+------+---------+--------------------------------------+
| 1    | abc     | ...                                  |
| 2    | def     | ...                                  |
| 3    | ghi     | ...                                  |
| 4    | def     | ...                                  |
| 5    | jkl     | ...                                  |
+------+-------+----------------------------------------+

表2

+------+--------+---------------------------------------+
| id   | tailID | value   |  others                     |
+------+--------+---------------------------------------+
| 1    | 2      | 412     |                             |
| 2    | 3      | 215     |                             |
| 1    | 2      | 571     |                             |
| 1    | 4      | 123     |                             |
+------+--------+---------------------------------------+

我喜欢将这两个表中的所有列连接到匹配的tail = tailID,但不是具有相同尾部的重复行.

对于重复的TAIL,只需要获得相同尾部的最大VALUE的单行.

我目前正在使用

SELECT table1.tail, table2.other_column 
FROM table1 
INNER JOIN table2 
on table1.id = table2.tailID 
WHERE table1.some_coloum = "a sepecific string" 
ORDER BY table2.value

但它会返回许多相同尾部的副本.

我只需要对于具有高位值tableuE 2的重复TAIL有单行.

解决方法:

disTINCT与交叉申请：

SELECT disTINCT t1.tail,
                t2.other_column,
                t3.[value]
FROM table1 t1
CROSS APPLY (
    SELECT  tailid,
            MAX([value]) as [value]
    FROM table2
    WHERE tailid = t1.id
    GROUP BY tailid
    ) as t3
INNER JOIN table2 t2
    ON t2.tailid = t3.tailid AND t3.[value] = t2.[value]
WHERE t1.some_coloum = "a sepecific string"