我有html内容存储在数据库表中.在那个html内容中我想用链接标签替换“SOME WORDS”.但如果“SOME WORDS”已经在链接标签中,我应该省略它们.
例如
内容
<p>Lorem ipsum dolor SOME WORDS, consectetur adipiscing elit. <a href="http://example.com">SOME WORDS</a> elementum pharetra velit at cursus. Quisque blandit, nibh at eleifend ullamcorper</p>
输出应该是
<p>Lorem ipsum dolor <a href="http://someurl">SOME WORDS</a>, consectetur adipiscing elit. <a href="http://example.com">SOME WORDS</a> elementum pharetra velit at cursus. Quisque blandit, nibh at eleifend ullamcorper</p>
如您所见,它应该在替换时排除现有的链接文本.
非常感谢一些指导,以进入正确的轨道.
解决方法:
这是使用DOMDocument而不是正则表达式来解决它的方法:
$contents = <<<EOS
<p>Lorem ipsum dolor SOME WORDS, consectetur adipiscing elit. <a href="http://example.com">SOME WORDS</a> elementum pharetra velit at cursus. Quisque blandit, nibh at eleifend ullamcorper</p>
EOS;
$doc = new DOMDocument;
libxml_use_internal_errors(true);
$doc->loadHTML($contents);
libxml_clear_errors();
$xp = new DOMXPath($doc);
// find all text nodes
foreach ($xp->query('//text()') as $node) {
// make sure it's not inside an anchor
if ($node->parentNode->nodeName !== 'a') {
$node->nodeValue = str_replace(
'SOME WORDS',
'SOME OTHER WORDS',
$node->nodeValue
);
}
}
// DOMDocument creates a full document and puts your fragment inside a body tag
// So we enumerate the children and save their HTML representation
$body = $doc->getElementsByTagName('body')->item(0);
foreach ($body->childNodes as $node) {
echo $doc->saveHTML($node);
}
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