我用json_encoded将数据插入数据库.
现在我想搜索“功能”,但我不能.
现在我想搜索“功能”,但我不能.
MySQL查询:
SELECT `id`,`attribs_json` FROM `products` WHERE `attribs_json` REGEXP '"1":{"value":[^"3"$]'
这个查询显示了所有的行与键“1”,值是任何东西,不是值“3”
我的资料是:
{"feature":{"1":{"value":"["2","3"]"},"2":{"value":["1"]},"5":{"value":""},"3":{"value":["1"]},"9":{"value":""},"4":{"value":"\u0633\u0627\u062a\u0646"},"6":{"value":""},"7":{"value":""},"8":{"value":""} },"show_counter":"0","show_counter_discount":"" }}
如果你有MysqL版本> = 5.7,那么你可以试试这个 –
SELECT JSON_EXTRACT(name,"$.id") as name FROM table WHERE JSON_EXTRACT(name,"$.id") > 3
输出 –
+-------------------------------+ | name | +-------------------------------+ | {"id": "4","name": "Betty"} | +-------------------------------+
请查看参考链接了解更多详情https://dev.mysql.com/doc/refman/5.7/en/json-search-functions.html
原文地址:https://www.jb51.cc/php/131553.html
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