PHP将二维数组某一个字段相同的数组合并起来的方法

本文实例讲述了PHP将二维数组某一个字段相同的数组合并起来的方法。分享给大家供大家参考，具体如下：

例子：

array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [2]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } }

现在想要对这个二维数组下的元素，time相同的合并到同一数组下。想要的效果为：

array(1) { [0]=> array(16) { ["id"]=> string(2) "42" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1443927600" ["createtime"]=> string(10) "1443880619" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月04日" ["date"]=> string(6) "周日" ["uname"]=> NULL ["album"]=> string(0) "" } } ["10月09日"]=> array(2) { [0]=> array(16) { ["id"]=> string(2) "40" ["uid"]=> string(2) "14" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359600" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } [1]=> array(16) { ["id"]=> string(2) "43" ["uid"]=> string(1) "2" ["euid"]=> string(2) "56" ["did"]=> string(1) "1" ["nid"]=> string(1) "0" ["phonetime"]=> string(10) "1444359620" ["createtime"]=> string(10) "1444268595" ["type"]=> string(1) "3" ["status"]=> string(1) "0" ["atype"]=> string(1) "1" ["mtype"]=> string(1) "2" ["endtime"]=> string(1) "0" ["time"]=> string(10) "10月09日" ["date"]=> string(6) "周五" ["uname"]=> NULL ["album"]=> string(0) "" } } }

那么。。。代码很简单，没有想象的那么复杂，想要的结果是个三维数组

$result 为原二维数组

$v) { $res[$v['time']][] = $v; }

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希望本文所述对大家PHP程序设计有所帮助。

原文地址：https://www.jb51.cc/php/20322.html