php 查询数据库显示小图，点击小图弹出大图的功能实例

PHP查询数据库显示小图，点击小图弹出大图，感兴趣的小伙伴，下面一起跟随编程之家 jb51.cc的小编来看看吧。
经测试代码如下：

/**
 * 查询数据库显示小图，点击小图弹出大图
 *
 * @param 
 * @arrange (编程之家) jb51.cc
 **/
//Get all the images in the database (use a WHERE clause to limit what it finds) 
$sql = MysqL_query(SELECT * FROM database_name); 
//Start A counter we will start at 1
$i = 1; 
//Get all the returned results,save them in an array,and loop throught the array 
//to display all the returned results 
while($row = MysqL_fetch_array($sql)){ 
    //Create a list from the returned image file,and make a $width and $height variable 
    list($width,$height) = getimagesize(url/to/large/image/.$row['img_file_name']); 
    //Add 30 to the returned width and height so it will fit in the popup window 
    //If it still doesn't fit,change the two thirtys to a larger number. 
    $width += 30; 
    $height += 30; 
    //Use javascript to make the popup 
    //Everytime the script runs through,$i will change so we can have dynamic popup window sizes 
    echo  
    <script type=text/javascript> 
        function load.$i.(){ 
            var load = window.open('url/to/large/image/.$row['img_file_name'].',' ','scrollbars=no,menubar=no,height=.$height.,width=.$width.,resizable=no,toolbar=no,location=no,status=no'); 
        } 
    </script>; 
    //This will display our thumbnail on the screen and make a link to the popup function 
    //that was just created in the above javascript. 
    echo' 
    <p> 
        <a href=javascript:load'.$i.'()> 
        <img src=url/to/thumb/image/'.$row['img_file_name'].' /> 
        </a> 
    </p>'; 
    //Add one to $i 
    $i++; 
} 


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