php – 如何将字符串转换为数组字符

第一行代码转换为第二个代码.我可以使用填充方法,但我希望从最短路径获得解决方案并快速转换.我将使用sql select部分中的代码字段

 $it = "(a(am,bam),b(dam,cam))";
 $to = "a.am,a.bam,b.dam,b.cam";

解决方法

请尝试以下代码：

$it = "(a(am,cam))";

function iDelimiter( $str ) {

    $count = 0;
    $str = str_split( $str );

    foreach( $str as &$value ) {

        if( $value == "(" ) {
            $count++;
        } elseif( $value == ")" ) {
            $count--;
        }

        if( $value == "," && ! $count ) {
            $value = "|";
        }

    }

    return explode( "|",implode( $str ) );

}

function iParser( $str,$_prefix = "" ) {

    preg_match( "/^((?!(\(|\))).)*\((.*)\)$/",$str,$m );

    if( count( $m ) < 4 ) {
        return ( strlen( $_prefix ) ? $_prefix . "." : '' ) . $str;
    }

    $prefix = ( strlen( $_prefix ) ? $_prefix . "." : '' ) . $m[1];

    $str = $m[3];

    if( strpos( $str,"(" ) === false ) {

        $return = explode( ",",$str );

        $pad = preg_filter( '/^/',strlen( $prefix ) ? $prefix . '.' : '',$return );

        return implode( $pad," );
    } else {

        $str = iDelimiter( $str );

        $return = array_map( 'iParser',array_pad( array(),count( $str ),$prefix ) );

        return implode( $return," );
    }

}

print_r( iParser( $it ) );

它解析括号的每个深度.只需将您的字符串传递给iParser函数即可.