我的正则表达式如下:
(?<![\s]*?(\"|")")WORD(?![\s]*?(\"|"))
正如你所看到的,我试图匹配WORD的所有实例,除非它们在“引号”内.所以…
WORD <- Find this "WORD" <- Don't find this " WORD " <- Also don't find this,even though not touching against marks "WORD" <- Dont find this (I check " and " so works after htmlspecialchars)
我相信我的正则表达式会完美地工作如果我没有收到错误:
Compilation Failed: lookbehind assertion is not fixed length
考虑到外观的局限性,有没有办法做我想做的事情?
如果您能想到其他任何方式让我知道.
非常感谢,
马修
附: WORD部分实际上包含Jon Grubers URL检测器
解决方法
我建议采用不同的方法.只要引号被正确平衡,这将起作用,因为你知道你在引用的字符串中iff后面的引号数是奇数,从而使lookbehind部分不必要:
if (preg_match( '/WORD # Match WORD (?! # unless it\'s possible to match the following here: (?: # a string of characters (?!") # that contains neither " [^"] # nor " )* # (any length),("|") # followed by either " or " (remember which in \1) (?: # Then match (?:(?!\1).)*\1 # any string except our quote char(s),followed by that quote char(s) (?:(?!\1).)*\1 # twice,)* # repeated any number of times --> even number (?:(?!\1).)* # followed only by strings that don\'t contain our quote char(s) $ # until the end of the string ) # End of lookahead/sx',$subject))
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