as easy problem

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16297    Accepted Submission(s): 10937

Problem Description

we define f(A) = 1,f(a) = ⑴,f(B) = 2,f(b) = ⑵,... f(Z) = 26,f(z) = ⑵6;
Give you a letter x and a number y,you should output the result of y+f(x).

 

Input

On the first line,contains a number T.then T lines follow,each line is a case.each case contains a letter and a number.

 

Output

for each case,you should the result of y+f(x) on a line.

 

Sample Input

6 R 1 P 2 G 3 r 1 p 2 g 3

 

Sample Output

19 18 10 ⑴7 ⑴4 ⑷

 

#include<stdio.h>

main()
{
char c;
int a,b,d,s,n,w,i,q;
scanf(%d,&q);
getchar();
//while(n--)
for(i=0;i<q;i++)
{
scanf(%c%d,&c,&s);
if(c>='A'&&c<='Z')
{a=c-'0'⑴6;
w=a+s;
//printf(%d ,w);
}
//continue;
if(c>='a'&&c<='z')
    {b=c-'0';
    b=b⑷8;
    a=-b;
   w=a+s;
   //printf(%d ,w);
//continue;
}
printf(%d ,w);
getchar();
}
  
return 0;
}