我正在使用postgresql 9.1,我想使用这个提示从我的表中删除重复项:
https://stackoverflow.com/a/3822833/2239537
https://stackoverflow.com/a/3822833/2239537
所以,我的查询看起来像这样:
WITH cte AS (SELECT ROW_NUMBER() OVER (PARTITION BY code,card_id,parent_id ORDER BY id DESC) RN FROM card) DELETE FROM cte WHERE RN > 1
但它告诉我
ERROR: relation "cte" does not exist sql state: 42P01 Character: 157
但是这个说法很好:
WITH cte AS (SELECT ROW_NUMBER() OVER (PARTITION BY code,parent_id ORDER BY id DESC) RN FROM merchantcard) SELECT * FROM cte WHERE RN > 1
任何想法如何让它工作?
谢谢!
这是因为Postgresql中的CTE与sql Server中的CTE不同.在sql Server中,CTE就像一个可更新的视图,所以你可以从它们中删除或更新它们,在Postgresql中你不能.
你可以加入cte和delete,如:
with cte as ( select id,row_number() over(partition by code,parent_id order by id desc) as rn from card ) delete from card where id in (select id from cte where rn > 1)
另一方面,您可以在Postgresql中的CTE中编写DDL语句(参见documentation),这可能非常方便.例如,您可以从卡中删除所有行,然后仅插入具有row_number = 1的行:
with cte1 as ( delete from card returning * ),cte2 as ( select row_number() over(partition by code,parent_id order by id desc) as rn,* from cte1 ) insert into card select <columns here> from cte2 where rn = 1
原文地址:https://www.jb51.cc/postgresql/192040.html
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。