查询:
SELECT COUNT(*) as count_all,posts.id as post_id FROM posts INNER JOIN Votes ON Votes.post_id = posts.id GROUP BY posts.id;
在Postgresql中返回n条记录:
count_all | post_id -----------+--------- 1 | 6 3 | 4 3 | 5 3 | 1 1 | 9 1 | 10 (6 rows)
我只想检索返回的记录数:6。
SELECT COUNT(*) FROM ( SELECT COUNT(*) as count_all,posts.id as post_id FROM posts INNER JOIN Votes ON Votes.post_id = posts.id GROUP BY posts.id ) as x;
我想你只需要COUNT(disTINCT post_id)从投票。
请参阅http://www.postgresql.org/docs/current/static/sql-expressions.html中的“4.2.7。汇总表达式”部分。
原文地址:https://www.jb51.cc/postgresql/193146.html
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