如何从请求中获取POST数据？

我只是用django设置了一个apache服务器,并测试它,在views.py中创建了一个非常简单的函数

channel = rabbit_connection()
@csrf_protect
@csrf_exempt
def index(request): 
    data={'text': 'Food truck is awesome! ','email': '[e-mail]','name': 'Bob'}
    callback(json.dumps(data))   
    context = RequestContext(request)    
    return render_to_response('index.html',context_instance=context)

如果我向服务器发送GET或POST请求,此函数可以正常工作.但是,我想从POST请求中获取此数据.假设我发送这样的请求：

import pycurl
import simplejson as json

data = json.dumps({'name':'Bob','email':'[e-mail]','text': u"Food truck is awesome!"})

c = pycurl.Curl()
c.setopt(c.URL,'http://ec2-54-......compute-1.amazonaws.com/index.html')
c.setopt(c.POSTFIELDS,data)
c.setopt(c.VERBOSE,True)

for i in range(100):
    c.perform()

我想在视图中看到的是这样的：

 if request.method == 'POST':
     data = ?????? # Something that will return me my dictionary

以防万一：
     它始终采用JSON格式,字段未知.

最佳答案

data = request.POST.get(‘data’,”)

将从您的字典中返回单个值(key = data).如果你想要整个字典,你只需使用request.POST.您在这里使用QueryDict类：

In an HttpRequest object,the GET and POST attributes are instances of django.http.QueryDict. QueryDict is a dictionary-like class customized to deal with multiple values for the same key. This is necessary because some HTML form elements,notably,pass multiple values for the same key.

QueryDict instances are immutable,unless you create a copy() of them. That means you can’t change attributes of request.POST and request.GET directly.

–Django Docs