本文小编为大家详细介绍“Python爬虫字体加密问题怎么解决”,内容详细,步骤清晰,细节处理妥当,希望这篇“Python爬虫字体加密问题怎么解决”文章能帮助大家解决疑惑,下面跟着小编的思路慢慢深入,一起来学习新知识吧。
抛出问题
F12 又是这样就比较麻烦,不能直接获取.
用requests库也是获取不到正常想要的 源码的,因为字体加密了.
解决步骤
获取到真正的源码
找到对应的字体库
进行解析操作.
获取到真正的源码
为什么用webdriver,因为
requests拿不到真正的源码.
from selenium import webdriver # --- 进行chrome的配置 options = webdriver.ChromeOptions() prefs = {"profile.managed_default_content_settings.images": 2} # 设置无图模式 options.add_experimental_option("prefs", prefs) options.add_argument("service_args = ['–ignore-ssl-errors = true', '–ssl-protocol = TLSv1']") options.binary_location = r'C:\Program Files\Google\Chrome\Application\chrome.exe' # ---- chrome进行端口接管调用 options.add_argument('-incognito') driver = webdriver.Chrome(options=options) driver.set_page_load_timeout(5) # --- 设置宽和高位置 driver.maximize_window() # --- 拦截webdriver检测代码 driver.execute_cdp_cmd("Page.addScriptToEvaluateOnNewDocument", {"source": """ Object.defineProperty(navigator, 'webdriver', { get: () => undefined }) """})
找到对应的字体库
# 示例 import base64 # 省略了很长的... b64_code = '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' with open('font.ttf', 'wb') as f: f.write(base64.decodebytes(b64_code.encode())) from fontTools.ttLib import TTFont # 导包 font = TTFont('font.ttf') font.saveXML('font.xml')
# 简单封装下 import base64 def w_tff(one_html): res_tff = re.findall(r';base64,(.*?)"', one_html, re.S) if res_tff and len(res_tff) == 1: new_res_ttf = res_tff[0] with open('123_new_ttf.ttf', 'wb') as f: f.write(base64.decodebytes(new_res_ttf.encode()))
from fontTools.ttLib import TTFont def get_num_phone(es_str: str): # 加载字体生成映射关系 path = '123_new_ttf.ttf' font = TTFont(path) # font.saveXML('font.xml') # 生成xml文件 # 得到映射关系 bestcmap = font.getBestCmap() ss = {} for key, value in bestcmap.items(): keys = hex(key).replace('0x', '').replace("&#x", "") # 10进制转16进制 if value == "zero": value = 0 elif value == "one": value = 1 elif value == "one": value = 1 elif value == "two": value = 2 elif value == "three": value = 3 elif value == "four": value = 4 elif value == "five": value = 5 elif value == "six": value = 6 elif value == "seven": value = 7 elif value == "eight": value = 8 elif value == "nine": value = 9 elif value == "hyphen": value = "-" ss.update({ keys: value }) need_re = es_str list_phone = "" try: for item in need_re.split(";"): if item: new_item = item.replace("&#x", "") list_phone += "".join(str(ss[new_item])) if not list_phone or len(list_phone) < 2: return None return list_phone except Exception as e: return None
<cmap> <tabLeversion version="0"/> <cmap_format_4 platformID="0" platEncID="3" language="0"> <map code="0x23" name="numbersign"/><!-- NUMBER SIGN --> <map code="0x2a" name="asterisk"/><!-- ASTERISK --> <map code="0x2b" name="plus"/><!-- PLUS SIGN --> <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS --> <map code="0x2f" name="slash"/><!-- SOLIDUS --> </cmap_format_4> <cmap_format_0 platformID="1" platEncID="0" language="0"> <map code="0x23" name="numbersign"/> <map code="0x2a" name="asterisk"/> <map code="0x2b" name="plus"/> <map code="0x2d" name="hyphen"/> <map code="0x2f" name="slash"/> </cmap_format_0> <cmap_format_4 platformID="3" platEncID="1" language="0"> <map code="0x23" name="numbersign"/><!-- NUMBER SIGN --> <map code="0x2a" name="asterisk"/><!-- ASTERISK --> <map code="0x2b" name="plus"/><!-- PLUS SIGN --> <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS --> <map code="0x2f" name="slash"/><!-- SOLIDUS --> </cmap_format_4> <cmap_format_12 platformID="3" platEncID="10" format="12" reserved="0" length="76" language="0" nGroups="5"> <map code="0x23" name="numbersign"/><!-- NUMBER SIGN --> <map code="0x2a" name="asterisk"/><!-- ASTERISK --> <map code="0x2b" name="plus"/><!-- PLUS SIGN --> <map code="0x2d" name="hyphen"/><!-- HYPHEN-MINUS --> <map code="0x2f" name="slash"/><!-- SOLIDUS --> <map code="0x880fb" name="zero"/><!-- ???? --> <map code="0x880fc" name="one"/><!-- ???? --> <map code="0x880fd" name="two"/><!-- ???? --> <map code="0x880fe" name="three"/><!-- ???? --> <map code="0x880ff" name="four"/><!-- ???? --> <map code="0x88100" name="five"/><!-- ???? --> <map code="0x88101" name="six"/><!-- ???? --> <map code="0x88102" name="seven"/><!-- ???? --> <map code="0x88103" name="eight"/><!-- ???? --> <map code="0x88104" name="nine"/><!-- ???? --> </cmap_format_12> </cmap>
读取ttf文件,(再生成xml文件,第一次寻找映射关系是需要做的)
font.getBestCmap()
获取映射关系表我们观察 xml文件的
cmap
段进行研究 ,可以看到我们明确需要的结果keys = hex(key).replace('0x', '').replace("&#x", "")
10进制转16进制 ,会得到映射关系表{'23': 'numbersign', '2a': 'asterisk', '2b': 'plus', '2d': '-', '2f': 'slash', '8826e': 0, '8826f': 1, '88270': 2, '88271': 3, '88272': 4, '88273': 5, '88274': 6, '88275': 7, '88276': 8, '88277': 9}
和从页面上那些来的结果 进行 逐个匹配调整就行了.
注意的点
webdriver拿下来的页面源码有可能有点问题,所以我用了 soup_text = bs4.BeautifulSoup(driver.page_source, 'lxml').text
的方法来处理源代码 (import bs4
)其他的就是一些小细节上的问题了.基本的思路就是这样的.
读到这里,这篇“Python爬虫字体加密问题怎么解决”文章已经介绍完毕,想要掌握这篇文章的知识点还需要大家自己动手实践使用过才能领会,如果想了解更多相关内容的文章,欢迎关注编程之家行业资讯频道。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。