我正在尝试使用var的名称来调用函数,但我不知道这是否可行,类似于:
fight_movies = list() # var how I want to use in function call win_movies = list() # var how I want to use in function call kNowledge_movies = list() # var how I want to use in function call biography_movies = list() # var how I want to use in function call for genre in genres: .... Ommited #\/\/\/\/\/\/ Here is where I call the function write_jsonl(genre + '_movies',genre,rating,title,genre) #here is the call of the function def write_jsonl(movie_list,json_name): dict = {'title': title,'genre': genre,'rating': rating} movie_list.append(dict) # print(action_movies) with jsonlines.open(json_name+'.jsonl',mode='w') as writer: writer.write(movie_list)
我正在尝试动态地将变量名称作为列表传递,但我不确定在python中是否可以使用任何建议?
Error: Traceback (most recent call last): File "bucky.py",line 58,in <module> web_crawling() File "bucky.py",line 34,in web_crawling write_jsonl(genre + '_movies',genre) File "bucky.py",line 52,in write_jsonl movie_list.append(dict) AttributeError: 'str' object has no attribute 'append'
解决方法
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