python – 在标签BeautifulSoup中显示文本

我试图只显示标签内的文字,例如：

<span class="listing-row__price ">$71,996</span>

我只想表现出来

“$71,996”

我的代码是：

import requests
from bs4 import BeautifulSoup
from csv import writer

response = requests.get('https://www.cars.com/for-sale/searchresults.action/?mdId=21811&mkId=20024&page=1&perPage=100&rd=99999&searchSource=PAGINATION&showMore=false&sort=relevance&stkTypId=28880&zc=11209')

soup = BeautifulSoup(response.text,'html.parser')

cars = soup.find_all('span',attrs={'class': 'listing-row__price'})
print(cars)

我哪里错了？

解决方法

要获取标记内的文本,有几种方法,

a)使用标记的.text属性.

cars = soup.find_all('span',attrs={'class': 'listing-row__price'})
for tag in cars:
    print(tag.text.strip())

产量

$71,996
$75,831
$71,412
$75,476
....

b)使用get_text()

for tag in cars:
    print(tag.get_text().strip())

c)如果标签内只有该字符串,您也可以使用这些选项

> .string
> .contents [0]
>下一个(tag.children)
> next(tag.strings)
> next(tag.stripped_strings)

即.

for tag in cars:
    print(tag.string.strip()) #or uncomment any of the below lines
    #print(tag.contents[0].strip())
    #print(next(tag.children).strip())
    #print(next(tag.strings).strip())
    #print(next(tag.stripped_strings))

输出：

$71,476
$77,001
...

注意：

.text和.string不一样.如果标记中有其他元素,则.string返回None,而.text将返回标记内的文本.

from bs4 import BeautifulSoup
html="""
<p>hello <b>there</b></p>
"""
soup = BeautifulSoup(html,'html.parser')
p = soup.find('p')
print(p.string)
print(p.text)

输出

None
hello there