正则表达式解析docker标签？

'registry/rabbit','registry/rabbit:3','rabbit','rabbit:3'

试图在上述四种情况下提出一种与兔子相匹配的正则表达式.似乎很容易,但我的正则表达式让我失望.

解决方法

你可以试试：

(?:[a-z]+/)?([a-z]+)(?::[0-9]+)?

但是您需要阅读规范以将a-z和0-9替换为所有可能的字符.

或者,此正则表达式将捕获容器名称,而不考虑除/和::之外的规范

(?:.+/)?([^:]+)(?::.+)?

样本数据和测试

def s = [
    'registry.example.com/org/image-name','registry/org/image-name','registry/image-name','image-name','registry.example.com/org/image-name:version','registry/org/image-name:version','registry/image-name:version','image-name:version',]

s.forEach {
    def image = (s =~ "(?:.+/)?([^:]+)(?::.+)?")[0][1]
    println image
    assert image == 'image-name'
}

将输出：

image-name
image-name
image-name
image-name
image-name
image-name
image-name
image-name