在独立(不是rails)的ruby应用程序中使用slim或haml来指定布局和模板

我想在独立(不是rails)的应用程序中做这样的事情：

layout.slim：

h1 Hello
.content
  = yield

show.slim：

= object.name
= object.description

我不知道如何指定布局和模板.这是可能与苗条(或哈姆尔)吗？谢谢.

解决方法

layout.slim文件如下所示：

h1 Hello
.content
  == yield

contents.slim文件如下所示：

= name

这可以缩短,但是为了解释目的,我分离到单独的步骤.

require 'slim'

# Simple class to represent an environment
class Env
  attr_accessor :name
end

# Intialize it
env = Env.new
# Set the variable we reference in contents.slim
env.name = "test this layout"

# Read the layout file in as a string
layout = File.open("layout.slim","rb").read

# Read the contents file in as a string
contents = File.open("contents.slim","rb").read

# Create new template object with the layout
l = Slim::Template.new { layout }

# Render the contents passing in the environment: env
# so that it can resolve: = name
c = Slim::Template.new { contents }.render(env)

# Render the layout passing it the rendered contents
# as the block. This is what yield in layout.slim will get
puts l.render{ c }

这将输出：

<h1>Hello</h1><div class="content">test this layout</div>

原文地址：https://www.jb51.cc/ruby/266332.html