ruby-on-rails-3 – 错误：运算符不存在：字符变化=整数

我面临着共同的问题.我的Rails应用程序在我的本地机器上工作,但是在部署到heroku之后它崩溃了：

<% unless @user.hotels.empty? %>
  <% @user.hotels.each do |hotel| %>
    <%= "#{hotel.description} #{hotel.name} in #{hotel.city},#{hotel.country}" %><br />
  <% end %>
<% end %>

这是从heroku日志：

ActionView::Template::Error (PGError: ERROR:  operator does not exist: character varying = integer
LINE 1: SELECT "hotels".* FROM "hotels" WHERE ("hotels".user_id = 1)
                                                                ^
HINT:  No operator matches the given name and argument type(s). You might need to add explicit type casts.
: SELECT "hotels".* FROM "hotels" WHERE ("hotels".user_id = 1)):

@ user.hotels.empty？创建错误.我知道,sqlite是相当原谅,但Postgresql不是.这是酒店型号的外键：user_id：integer

Heroku说：

Make sure the operator is adequate for the data type. ActiveRecord does this automatically when you use an interpolated condition form.

Array conditions:
:conditions => ['column1 = ? AND column2 = ?',value1,value2]

Hash conditions:
:conditions => { :column1 => value1,:column2 => value2 }

迁移如下所示：

class CreateHotels < ActiveRecord::Migration
  def self.up
    create_table :hotels do |t|
      t.string :name
      t.string :vanity_url
      t.integer :user_id
      ....

解决方法

这通常发生在数据库中的外键不是整数时.

例如：

LINE 1: SELECT "hotels".* FROM "hotels" WHERE ("hotels".user_id = 1)
                                                                ^

在这种情况下,Postgresql希望user_id是一个整数,但它几乎看起来像是告诉你它实际上是一个varchar.

我会尝试删除列并重新添加.

原文地址：https://www.jb51.cc/ruby/272899.html