斯卡拉 – varargs拼图？

我确定答案很简单,但我陷入了困境：

Welcome to Scala version 2.7.1.final (Java HotSpot(TM) 64-Bit Server VM,Java 1.6.0_14).
Type in expressions to have them evaluated.
Type :help for more information.

scala> def f(x:Int*)=0
f: (Int*)Int

scala> val xs:Seq[Int]=1::2::3::4::Nil
xs: Seq[Int] = List(1,2,3,4)

scala> f (xs)
<console>:7: error: type mismatch;
 found   : Seq[Int]
 required: Int
       f (xs)
          ^

我如何构建’Int *’？

解决方法

要将序列解压缩到参数列表中,请使用_ *

scala> f(xs: _*)
res1: Int = 0