java – 如何通过spring 4 resttemplate发送收到的jsessionid

我正在客户端站点上使用JavaFX和Spring4编写信使,在服务器站点上编写Spring4.我用spring-security 3.2保护了服务器.现在我的问题：我在客户端上有一个登录页面,将登录信息发送到spring-security并接收JSESSIONID cookie.这工作正常,但当我尝试用我的请求发送JSESSIONID时,我变成了一个

org.springframework.web.client.RestClientException: Could not extract response: no suitable HttpMessageConverter found for response type [class org.messenger.rest.JSONConversationResult] and content type [text/html;charset=UTF-8]

服务器Inizializer

public class SpringMvcInitializer extends
    AbstractAnnotationConfigdispatcherServletinitializer {

    @Override
    protected ClassfigClasses() {
        return new Class[] {ApplicationConfig.class};
    }

    @Override
    protected ClassfigClasses() {
        return new Class[] {WebConfig.class};
    }

    @Override
    protected String[] getServletMappings() {
        return new String[] {"/"};
    }
}

Server SecurityInizializer

public class SpringSecurityInitializer extends
    AbstractSecurityWebApplicationInitializer {
}

Server SecurityConfig

@Configuration
@EnableWebSecurity
public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Autowired
    private DriverManagerDataSource dataSource;

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        String authQuery = "select userid,authority from user where userid = ?";
        String userQuery = "select userid,pw,enabled from user where userid = ?";

        auth.jdbcAuthentication().dataSource(dataSource)
            .passwordEncoder(passwordEncoder())
            .usersByUsernameQuery(userQuery)
            .authoritiesByUsernameQuery(authQuery);

    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {


        http
            .authorizeRequests()
                .antMatchers("/register").permitAll()
                .antMatchers("/getconvs","/getcontacts").hasRole("USER")
                .and()
            .formLogin()
                .and()
            .csrf().disable();
    }

    @Bean
    public AuthenticationEntryPoint authenticationEntryPoint() {
        return new de.daschner.messenger.security.AuthenticationEntryPoint();
    }

    @Bean
    public SuccessHandler successHandler() {
        return new SuccessHandler();
    }

    @Bean
    public SimpleUrlAuthenticationFailureHandler failureHandler() {
        return new SimpleUrlAuthenticationFailureHandler();
    }

    @Bean
    public AuthenticationManager authenticationManager() throws Exception {
        return super.authenticationManager();
    }

    @Bean
    public PasswordEncoder passwordEncoder() {
    return new BCryptPasswordEncoder(11);
    }
}

安全“页面”的服务器请求映射

@RequestMapping(value="/getconvs",method={RequestMethod.GET},produces={MediaType.APPLICATION_JSON_VALUE})
public @ResponseBody JSONConversationResult getConvsList(HttpServletRequest request,@RequestParam(value="uid") String uid){
    JSONConversationResult ret = new JSONConversationResult();
    Map


客户端发送登录并获取Cookie

    Maphttpentityhttpentityhttpentityfig.getJsessionid());
        return new httpentity

我希望你能帮助我.
编辑：
好的我发现问题不在于JSESSIONID没有正确发送.但我的登录不正确,我的查询从数据库中获取用户.
正确的登录帖子

ClientHttpResponse response = restTemplate.execute(
            "http://localhost:8080/messenger-webapp/login",new RequestCallback() {

                @Override
                public void doWithRequest(ClientHttpRequest request) throws IOException {
                    request.getBody().write(("username=" + user + "&password=" + pw).getBytes());
                }
            },new ResponseExtractor

正确的查询

String authQuery = "select u.userid,r.role_name from user u,role r,user_role a where u.dbid = a.user_id and r.dbid = a.role_id and u.userid = ?";

我希望这会有助于其他人.如果有人有其他选择,请告诉我.


最佳答案
好的我发现问题不在于JSESSIONID没有正确发送.但我的登录不正确,请告诉我.
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java – 如何通过spring 4 resttemplate发送收到的jsessionid

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