如何转义特殊字符,如’在sqlite在android

我有一个函数，它在sqlite数据库中的表上执行查询。我声明一个常量：public static final String CANADA_HISTORY =“加拿大历史”;这个存储在一个String变量中我们说难度，

我有一个查询：

Cursor c = mDb.rawQuery("select * from Questions_answers where CHAPTERS = '"+difficulty+"'",null);

它在撇号附近抛出异常。

Logcat输出：

I/Database( 1170): sqlite returned: error code = 1,msg = near "s": Syntax error
D/AndroidRuntime( 1170): Shutting down VM
W/dalvikvm( 1170): threadid=1: thread exiting with uncaught exception (group=0x40015560)
E/AndroidRuntime( 1170): FATAL EXCEPTION: main
E/AndroidRuntime( 1170): android.database.sqlite.sqliteException: near "s": Syntax error:,while compiling: select * from Questions_answers where CHAPTERS  = 'Canada's History'

我也试过：

1.  difficulty=difficulty.replaceAll("'","''");
2.  difficulty=difficulty.replaceAll("'","\'");
3.  difficulty = DatabaseUtils.sqlEscapestring(difficulty);

除此之外，它还为我的单词，如加拿大历史，我的意思是没有特殊字符。

请给我建议解决问题谢谢。

首先用这个替换char

difficulty=difficulty.replaceAll("'","\'");

然后在您的查询中传递它

"select * from Questions_answers where CHAPTERS='"+difficulty+"'";

编辑：

q = "select * from Questions_answers where CHAPTERS = ?";
    database.rawQuery(q,new String[] { difficulty});

原文地址：https://www.jb51.cc/sqlite/198125.html