SQLite 中的递归

create table if not exists testTable( id INT PRIMARY KEY,[name] NVARCHAR(20),parentId INT );
INSERT INTO testTable(id,[name],parentId) VALUES(1,'xf1',0);
INSERT INTO testTable(id,parentId) VALUES(2,'xf2',parentId) VALUES(3,'xf3',2);
INSERT INTO testTable(id,parentId) VALUES(4,'xf4',3);
INSERT INTO testTable(id,parentId) VALUES(5,'xf5',4);
INSERT INTO testTable(id,parentId) VALUES(6,'xf6',5);

WITH RECURSIVE 
  cte(id,name,parentId) AS(
    SELECT id,parentId FROM testTable WHERE id='6'
    UNION ALL
    SELECT a.id,a.name,a.parentId FROM testTable AS a INNER JOIN 
        cte ON a.id=cte.parentId   
)
SELECT * FROM cte;

--得到1-10 的数
WITH RECURSIVE
  cnt(x) AS (VALUES(1) UNION ALL SELECT x+1 FROM cnt WHERE x<10)
SELECT x FROM cnt order by x;

WITH RECURSIVE
  cnt(x) AS (
     SELECT 1
     UNION ALL
     SELECT x+1 FROM cnt
      LIMIT 10
  )
SELECT x FROM cnt order by x;

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原文地址：https://www.jb51.cc/sqlite/198220.html