int数组转化成string数组(swift) 方法1: let nums = [1,2,3,4,5,6,7]
var strs = [String]()
for var i = 0; i < nums.count; ++i {
strs.append(String(nums[i]))
} 方法2: let nums = [1,2,3,4,5,6,7]
let strs = nums.ma
表示使用 swift中的结构实现的数字,字符和字符串的类型. 摘自official documentation: Data types that are normally considered basic or primitive in other languages—such as types that represent numbers, characters, and strings—are
我想知道是否有一种更简单的方法将这两个初始化程序编写为通用的初始化程序 public required init(_ value : Double) {
super.init(value: value, unitType: unit)
}
public required init(_ value : Int) {
let v = Double(value)
super.i
我们先来看一个简单的程序: #include <stdio.h>
#include <string.h>
int main(int argc, char *argv[])
{
int a = 1;
int b = (int)(void *)a;
printf("%d\n", b);
return 0;
}
结果是1 这引出下面一个问题: 如果一个函数