(1)如果类型不包含任何实例构造函数声明,则VB.NET提供默认的构造函数;
默认参数调用直接基类的无参数构造函数。如果基类没有可访问的无参数构造函数,则发生编译期错误。
(2)构造函数不能继承;
陈述(1)包含两个方面的信息:①是如果类型不包含任何实例构造函数声明,则VB.NET提供默认的构造函数,即下面的声明是允许的,在类Shape中我们没有显式声明任何构造函数,但是我们仍然可以通过VB.NET自动提供的无参数构造函数New()来实例化类;
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display='none'; CodeHighlighter1_20_72_Closed_Text.style.display='none'; CodeHighlighter1_20_72_Open_Image.style.display='inline'; CodeHighlighter1_20_72_Open_Text.style.display='inline';" id="CodeHighlighter1_20_72_Closed_Image" style="display: none" height="16" src="http://img.jb51.cc/vcimg/static/loading.png" width="11" align="top" src="http://www.cnblogs.com/Images/OutliningIndicators/ContractedSubBlock.gif">
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②是如果类型中包含有实例构造函数的声明,那么VB.NET不再提供默认的构造函数,例如,我们在类Shape中添加了一个带参数的构造函数,
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Public ClassShapePHP?refimg= + this.src)" height="16" src="http://img.jb51.cc/vcimg/static/loading.png" width="11" align="top" src="http://www.cnblogs.com/Images/OutliningIndicators/InBlock.gif">
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那么,如果直接实例化类时,则会产生错误;
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Dim shape1 As Shape = New Shape只能通过调用Shape类中显式声明的带参数的构造函数来实例化类,如下,
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Dim shape1 As Shape = New Shape( New Point( 0 , 0 ))因此,如果要在类中同时使用无参数和带参数的构造函数,必须同时显式地声明两种构造函数。
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display='none'; CodeHighlighter1_143_181_Closed_Text.style.display='none'; CodeHighlighter1_143_181_Open_Image.style.display='inline'; CodeHighlighter1_143_181_Open_Text.style.display='inline';" id="CodeHighlighter1_143_181_Closed_Image" style="display: none" height="16" src="http://img.jb51.cc/vcimg/static/loading.png" width="11" align="top" src="http://www.cnblogs.com/Images/OutliningIndicators/ContractedSubBlock.gif">
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陈述(2),构造函数不能继承,即,如果要使子类与基类有相同的构造函数,那么必须在每个子类中都显式的声明与基类构造相同的构造函数,例如:
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