一:建相关数据表
DROP TABLE IF EXISTS `dept`;
CREATE TABLE `dept` (
`DEPTNO` int(11) NOT NULL,
`DNAME` varchar(14) DEFAULT NULL,
`LOC` varchar(13) DEFAULT NULL,
PRIMARY KEY (`DEPTNO`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
-- ----------------------------
-- Records of dept
-- ----------------------------
INSERT INTO `dept` VALUES ('10', 'ACCOUNTING', 'NEW YORK');
INSERT INTO `dept` VALUES ('20', 'RESEARCH', 'DALLAS');
INSERT INTO `dept` VALUES ('30', 'SALES', 'CHICAGO');
INSERT INTO `dept` VALUES ('40', 'OPERATIONS', 'BOSTON');
-- ----------------------------
-- Table structure for emp
-- ----------------------------
DROP TABLE IF EXISTS `emp`;
CREATE TABLE `emp` (
`EMPNO` int(11) NOT NULL,
`ENAME` varchar(10) DEFAULT NULL,
`JOB` varchar(9) DEFAULT NULL,
`MGR` int(11) DEFAULT NULL,
`HIREDATE` date DEFAULT NULL,
`SAL` double DEFAULT NULL,
`COMM` double DEFAULT NULL,
`DEPTNO` int(11) DEFAULT NULL,
PRIMARY KEY (`EMPNO`),
KEY `EMP` (`DEPTNO`),
CONSTRAINT `emp_ibfk_1` FOREIGN KEY (`DEPTNO`) REFERENCES `dept` (`DEPTNO`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
-- ----------------------------
-- Records of emp
-- ----------------------------
INSERT INTO `emp` VALUES ('7369', 'SMITH', 'CLERK', '7902', '1980-12-17', '8000', null, '20');
INSERT INTO `emp` VALUES ('7499', 'ALLEN', 'SALESMAN', '7698', '1981-02-20', '1600', '300', '30');
INSERT INTO `emp` VALUES ('7521', 'WARD', 'SALESMAN', '7698', '1981-02-22', '1250', '500', '30');
INSERT INTO `emp` VALUES ('7566', 'JOnes', 'MANAGER', '7839', '1981-04-02', '2975', null, '20');
INSERT INTO `emp` VALUES ('7654', 'MARTIN', 'SALESMAN', '7698', '1981-09-28', '1250', '1400', '30');
INSERT INTO `emp` VALUES ('7698', 'BLAKE', 'MANAGER', '7839', '1981-05-01', '2850', null, '30');
INSERT INTO `emp` VALUES ('7782', 'CLARK', 'MANAGER', '7839', '1981-06-09', '2450', null, '10');
INSERT INTO `emp` VALUES ('7788', 'SCott', 'ANALYST', '7566', '1987-07-03', '3000', null, '20');
INSERT INTO `emp` VALUES ('7839', 'KING', 'PRESIDENT', null, '1981-11-17', '5000', null, '10');
INSERT INTO `emp` VALUES ('7844', 'TURNER', 'SALESMAN', '7698', '1981-09-08', '1500', '0', '30');
INSERT INTO `emp` VALUES ('7876', 'AdamS', 'CLERK', '7788', '1987-07-13', '1100', null, '20');
INSERT INTO `emp` VALUES ('7900', 'JAMES', 'CLERK', '7698', '1981-12-03', '950', null, '30');
INSERT INTO `emp` VALUES ('7902', 'FORD', 'ANALYST', '7566', '1981-12-03', '3000', null, '20');
INSERT INTO `emp` VALUES ('7934', 'MILLER', 'CLERK', '7782', '1981-01-23', '1300', null, '10');
INSERT INTO `emp` VALUES ('7935', 'WAYNE', 'CLERK', '7902', '1980-01-01', '1500', null, '10');
-- ----------------------------
-- Table structure for salgrade
-- ----------------------------
DROP TABLE IF EXISTS `salgrade`;
CREATE TABLE `salgrade` (
`GRADE` int(11) DEFAULT NULL,
`LOSAL` double DEFAULT NULL,
`HISAL` double DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
-- ----------------------------
-- Records of salgrade
-- ----------------------------
INSERT INTO `salgrade` VALUES ('1', '700', '1200');
INSERT INTO `salgrade` VALUES ('2', '1201', '1400');
INSERT INTO `salgrade` VALUES ('3', '1401', '2000');
INSERT INTO `salgrade` VALUES ('4', '2001', '3000');
INSERT INTO `salgrade` VALUES ('5', '3001', '9999');
-- ----------------------------
-- Table structure for user
-- ----------------------------
DROP TABLE IF EXISTS `user`;
CREATE TABLE `user` (
`id` int(11) NOT NULL,
`username` varchar(255) DEFAULT NULL,
`password` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
-- ----------------------------
-- Records of user
-- ----------------------------
INSERT INTO `user` VALUES ('1', '小红 ', '111');
INSERT INTO `user` VALUES ('2', '小刚', '222');
二:题目
#1、查找部门30中员工的详细信息。
select * from emp where deptno = 30;
#2、找出从事clerk工作的员工的编号、姓名、部门号。
select empno,ename,deptno from emp where job = 'clerk';
#3、检索出奖金多于基本工资的员工信息。
select * from emp where comm > sal;
#4、检索出奖金多于基本工资60%的员工信息。
select * from emp where comm > sal * 0.6;
#5、找出10部门的经理、20部门的职员 的员工信息。
select * from emp where deptno = 10 and job='MANAGER' or deptno = 20 and job = 'CLERK';
#6、找出10部门的经理、20部门的职员 或者既不是经理也不是职员但是工资高于2000元的员工信息。
select * from emp
where deptno = 10 and job='MANAGER'
or deptno = 20 and job = 'CLERK'
or job!='MANAGER' and job != 'CLERK' and sal > 2000 ;
## job not in ('MANAGER','CLERK')
#7、找出获得奖金的员工的工作。
select * from emp where comm > 0;
#8、找出奖金少于100或者没有获得奖金的员工的信息。
select * from emp where comm < 100 or comm is null;
#9、找出姓名以A、B、S开始的员工信息。
select * from emp where ename like 'A%' or ename like 'B%' or ename like 'S%';
#10、找到名字长度为6个字符的员工信息。
select * from emp where length(ename) = 6;
#select * from emp where ename like '______';
#11、名字中不包含R字符的员工信息。
select * from emp where ename not like '%r%';
#12、返回员工的详细信息并按姓名排序。
select * from emp order by ename asc;
#13、返回员工的信息并按工作降序工资升序排列。
select * from emp order by job desc , sal asc;
#14、计算员工的日薪(按30天)。
select ename,sal/30 as '日薪' from emp;
select ename,truncate(sal/30,2) '日薪' from emp;
#15、找出姓名中包含A的员工信息。
select * from emp where ename like '%A%';
多表查询答案
#1、返回拥有员工的部门名、部门号。
select distinct d.dname, d.deptno from dept d,emp e where d.deptno = e.deptno;
#2、工资水平多于smith的员工信息。
select *from emp where sal > (select sal from emp where ename = 'smith');
#3、返回员工和所属经理的姓名。
select e.ename,m.ename from emp e
left outer join emp m on e.mgr = m.empno;
select e.ename ,(select m.ename from emp m where m.empno = e.mgr) ename from emp e;
select e.ename , m.ename from emp e , emp m where e.mgr = m.empno;
#4、返回雇员的雇佣日期早于其经理雇佣日期的员工及其经理姓名。
select e.ename,m.ename from emp e
inner join emp m on e.mgr = m.empno
where e.hiredate < m.hiredate;
select e.ename,m.ename from emp e,emp m
where e.mgr=m.empno
and e.hiredate < m.hiredate;
#5、返回员工姓名及其所在的部门名称。
select e.ename,d.dname from emp e , dept d where e.deptno = d.deptno;
#6、返回从事clerk工作的员工姓名和所在部门名称。
select e.ename,d.dname
from emp e , dept d
where e.deptno = d.deptno and e.job = 'CLERK';
#7、返回部门号及其本部门的最低工资。
select deptno ,min(sal) sal
from emp
group by deptno
#8、返回销售部(sales)所有员工的姓名。
select e.ename from emp e,dept d
where e.deptno = d.deptno and d.dname = 'sales';
select ename from emp where deptno=(select deptno from dept where dname='sales');
#9、返回工资水平多于平均工资的员工。
select * from emp e
where e.sal > (select avg(sal) from emp);
#10、返回与SCott从事相同工作的员工。
select * from emp
where job = (select job from emp where ename = 'scott');
select e1.* from emp e1 , (select empno,job from emp where ename = 'scott') e2
where e1.job = e2.job and e1.empno != e2.empno;
#11、返回与30部门员工工资水平相同的员工姓名与工资。
select ename,sal from emp
where sal in (select sal from emp where deptno = 30);
#12、返回工资高于30部门所有员工工资水平的员工信息。
select * from emp
where sal > all(select sal from emp where deptno = 30);
select * from emp
where sal > (select max(sal) from emp where deptno = 30);
#13、返回部门号、部门名、部门所在位置及其每个部门的员工总数。
select dept.deptno,dept.dname,dept.loc,count(emp.deptno) number from dept,emp
where dept.deptno = emp.deptno
group by emp.deptno;
#14、返回员工的姓名、所在部门名及其工资。
select ename,dname,sal from emp ,dept
where emp.deptno = dept.deptno;
#15、返回员工的详细信息。(包括部门名)
select e.* , d.dname from emp e, dept d
where e.deptno = d.deptno;
#16、返回员工工作及其从事此工作的最低工资。
select job , min(sal) sal from emp
group by job
#17、计算出员工的年薪,并且以年薪排序。
select ename, sal * 12 as ySalary from emp order by ySalary;
#18、返回工资处于第四级别的员工的姓名。
select ename,sal from emp e ,salgrade s
where e.sal >= s.losal and e.sal <= s.hisal
and s.grade = 4;
select emp.ename,emp.sal from
emp ,(select losal,hisal from salgrade where grade=4) g
where emp.sal between g.losal and g.hisal;
#19、返回工资为二等级的职员名字、部门所在地、和二等级的最低工资和最高工资
select ename ,dname ,sal ,losal,hisal from emp,dept,salgrade
where emp.deptno = dept.deptno and grade = 2
and sal >= losal and sal < hisal;
#20.工资等级多于smith的员工信息。
select e.* from emp e, salgrade s
where s.hisal < e.sal and s.grade = (select grade from salgrade s ,emp e
where s.losal < e.sal and s.hisal > e.sal and e.ename = 'smith');
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