LeetCode 496. Next Greater Element I

Next Greater Element I

You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2.

The Next Greater Number of a number x in nums1 is the first greater number to its right in nums2. If it does not exist,output -1 for this number.

Example 1:
`

Input: nums1 = [4,1,2],nums2 = [1,3,4,2].
Output: [-1,-1]
Explanation:
                                        For number 4 in the first array,you cannot find the next greater number for it in the second array,so output -1.
                                        For number 1 in the first array,the next greater number for it in the second array is 3.
                                        For number 2 in the first array,there is no next greater number for it in the second array,so output -1.`
Example 2:

`

Input: nums1 = [2,4],2,4].
Output: [3,-1]
Explanation:
                                        For number 2 in the first array,the next greater number for it in the second array is 3.
                                        For number 4 in the first array,so output -1.

`
Note:
All elements in nums1 and nums2 are unique.
The length of both nums1 and nums2 would not exceed 1000.
解题思路：
创建一个新数组arr[]先将值都赋值为-1，然后遍历findNums数组中的元素同时获取对应在nums数组中相同元素的位置，再对nums数组进行遍历，获取到右边又大于当前元素的值时赋值给对应位置的arr[]数组。
具体代码：
`

/**
* @param {number[]} findNums
* @param {number[]} nums
* @return {number[]}
*/
var nextGreaterElement = function(findNums,nums) {
var l = nums.length-1,fl = findNums.length-1,arr = [];
for(var ifl=fl;ifl>=0;ifl--){
    arr.push(-1)
}
for(var i=0;i<=fl;i++){
    for(var ii=nums.indexOf(findNums[i]);ii<=l;ii++){
        if(findNums[i]fl){
    return arr 
}
 };

`