在Powershell中应该使用什么异常类型来捕获由于无效字符而导致的XML解析错误？

下面脚本中的第2行生成 –

“Cannot convert value “System.Object[]” to type
“System.Xml.XmlDocument”. Error: “‘→’,hexadecimal value 0x1A,is an
invalid character. Line 39,position 23.”

At line:1 char:8
+ [xml]$x <<<< = Get-Content 4517.xml
+ CategoryInfo : MetadataError: (:) [],ArgumentTransformationMetadataException
+ FullyQualifiedErrorId : RuntimeException”

应该在第4行(脚本)指定什么异常来捕获上述错误？

try {
    [xml]$xml = Get-Content $file # line 2
}
catch [?] {                       # line 4
    echo "XML parse error!"
    # handle the parse error differently
}
catch {
    echo $error
    # some general error
}

感谢您寻找(并回答)

阿德里安

这是一种发现自己的Exception的完整类型名称的方法,这里的结果给出了@Adrian Wright给出的System.Management.Automation.ArgumentTransformationMetadataException.

Clear-Host
try {
    [xml]$xml = Get-Content "c:\Temp\1.cs" # line 2
}
catch {
    # discovering the full type name of an exception
    Write-Host $_.Exception.gettype().fullName
    Write-Host $_.Exception.message
}