编组XML Go XMLName xmlns

我试图获得以下 XML输出

<?xml version="1.0" encoding="UTF-8"?>

<CreateHostedZoneRequest xmlns="https://route53.amazonaws.com/doc/2012-12-12/">
   <Name>DNS domain name</Name>
   <CallerReference>unique description</CallerReference>
   <HostedZoneConfig>
      <Comment>optional comment</Comment>
   </HostedZoneConfig>
</CreateHostedZoneRequest>

我有以下输出非常接近的XML,但我无法编码到CreateHostedZoneRequest

xmlns=”https://route53.amazonaws.com/doc/2012-12-12/

package main

import "fmt"
import "encoding/xml"

type ZoneRequest struct {
  Name            string
  CallerReference string
  Comment         string `xml:"HostedZoneConfig>Comment"`
}

var zoneRequest = ZoneRequest{
  Name:            "DNS domain name",CallerReference: "unique description",Comment:         "optional comment",}

func main() {
  tmp,_ := createHostedZoneXML(zoneRequest)
  fmt.Println(tmp)
}

func createHostedZoneXML(zoneRequest ZoneRequest) (response string,err error) {
  tmp := struct {
    ZoneRequest
    XMLName struct{} `xml:"CreateHostedZoneRequest"`
  }{ZoneRequest: zoneRequest}

  byteXML,err := xml.MarshalIndent(tmp,"",`   `)
  if err != nil {
    return "",err
  }
  response = xml.Header + string(byteXML)
  return
}

http://play.golang.org/p/pyK76VPD5-

如何将xmlns编码到CreateHostedZoneRequest中？

你可以这样做,这可能不是最优雅的解决方案,但似乎工作

Playground link

type ZoneRequest struct {
    Name            string
    CallerReference string
    Comment         string `xml:"HostedZoneConfig>Comment"`
    Xmlns           string `xml:"xmlns,attr"`
}

var zoneRequest = ZoneRequest{
    Name:            "DNS domain name",Xmlns:           "https://route53.amazonaws.com/doc/2012-12-12/",}

生产

<?xml version="1.0" encoding="UTF-8"?>

<CreateHostedZoneRequest xmlns="https://route53.amazonaws.com/doc/2012-12-12/">
   <Name>DNS domain name</Name>
   <CallerReference>unique description</CallerReference>
   <HostedZoneConfig>
      <Comment>optional comment</Comment>
   </HostedZoneConfig>
</CreateHostedZoneRequest>