将对象值保持在XML序列化和反序列化(C#)之间

我有一个要尝试使用XMLSerializer进行序列化和反序列化的类.该类如下所示：

namespace AutoCAD_Adapter
{
    /// <summary>
    /// Test class meant to be serialized to test serialization methods
    /// </summary>
    [Serializable]
    public class SerializeTest// : ISerializable
    {
        #region class variables
        private int x;
        private int y;
        #endregion

        #region Constructors
        public SerializeTest(int passedX, int passedY)
        {
            this.x = passedX;
            this.y = passedY;
        }

        private Serializetest()
        {

        }

        #endregion

        #region Public methods
        public void setX(int x)
        {
            this.x = x;
        }

        public int getX()
        {
            return this.x;
        }

        public void setY(int y)
        {
            this.y = y;
        }

        public int getY()
        {
            return this.y;
        }



        #endregion
    }
}

我知道XMLSerialization的类中没有空构造函数参数的问题,我通过创建私有默认构造函数来处理这些参数.注意到,这是我的实现：

public void XMLSave()
{
    SerializeTest input = new SerializeTest(4, 8); //Object to serialize
    using (MemoryStream stream = new MemoryStream())
    {
        XmlSerializer serializer = new XmlSerializer(st.GetType());
        serializer.Serialize(stream, input);
        stream.Position = 0;
        SerializeTest output = serializer.Deserialize(stream) as SerializeTest;
        MessageBox.Show(output.getX() + " " + output.getY(), "Output", MessageBoxButtons.OK);
    }
}

执行后,我希望MessageBox显示(4,8)的值,但显示(0,0).我需要能够在整个序列化过程中保留对象值,最好是在保持XML序列化的同时.

解决方法:

您的数据未序列化,因为它由专用字段保存.仅公共成员被序列化.如注释中所述,您是Java开发人员,因此您需要看一下properties.使用它们,您的模型可能如下所示：

public class SerializeTest
{
    public int X { get; set; }
    public int Y { get; set; }

    public SerializeTest(int x, int y)
    {
        X = x;
        Y = y;
    }

    public Serializetest()
    {
    }
}

现在,您可以轻松地对其进行序列化和反序列化：

var input = new SerializeTest(4, 8);

using (var ms = new MemoryStream())
{
    var serializer = new XmlSerializer(typeof(SerializeTest));
    serializer.Serialize(ms, input);
    ms.Position = 0;

    var output = serializer.Deserialize(ms) as SerializeTest;
}